Answer:
MOLARITY= 0.3092mol/l
ABSOLUTE UNCERTAINTY= 0.000873
Explanation:
The equation of reaction is
2HNO3 + Na2CO3 ⟶ 2NaNO3 + H2O + CO2.
QUESTION1: CALCULATION FOR MOLARITY;
Molarity= gram mole of solute ÷ liters of solution
Where;
Mole of solute= mass ÷ molar mass
Therefore;
Mole of solute= 0.8311g ÷ 105.988g/mol= 0.0078515mol
MOLARITY= 0.0078415mol ÷ 25.36ml = 0.0003092mol/ml = 0.3092mol/l
This is the Molarity of the solution
QUESTION2: CALCULATION FOR ABSOLUTE UNCERTAINTY;
Uncertainty (u) =√([0.05 ÷ 25.36]^2 + [0.001 ÷ 105.988]^2 + [0.0007 ÷ 0.8311]^2) × Molarity
Solving brackets gives
(0.00197161+0.00000943503+0.00084226) ×Molarity
Adding up gives
0.002823×Molarity
Therefore;
ABSOLUTE UNCERTAINTY= 0.002823×0.3092= 0.000873
Answer:
Protons have a much larger volume than neutrons.
Answer:
A. The object broke apart and seemed to disappear when dropped into the glass of water.
Explanation:
In a physical change, the physical properties of the matter usually the state of the matter is altered. Most physical changes are usually reversible and does not lead to the production of new substances.
When the solid object was dropped into the water beaker and it dissolves by disappearing the solution, we have experienced a physical change. This is a dissolution reaction. If we heat the solution and water given off, we can recover back the dissolved solid object.
<span>(K⁺¹)2Cr(O⁻²)4
+1*2 +x-2*4=0
2+x-8=0
x=6
Oxidation number of Cr is +6.</span>
Answer:
The correct option is
C) Trial 1 will have the same calculated empirical formula as trial 2.
Explanation:
The empirical formula is the formula of a chemical compound that states the simplest whole number ratio of each of the atoms included in the compound. It is obtained by dividing the mass of an element present in the compound by the element's molar mass to find the mole ratio of the elements. The obtained mole value for each element is then divided by the smallest number of moles obtained in the division.
By definition the composition and ratio of elements combined in a chemical compound is fixed, therefore trial 1 will have the same calculated empirical formula as trial 2.
