Answer:
The acceleration of the both masses is 0.0244 m/s².
Explanation:
Given that,
Mass of one block = 602.0 g
Mass of other block = 717.0 g
Radius = 1.70 cm
Height = 60.6 cm
Time = 7.00 s
Suppose we find the magnitude of the acceleration of the 602.0-g block
We need to calculate the acceleration
Using equation of motion

Where, s = distance
t = time
a = acceleration
Put the value into the formula



Hence, The acceleration of the both masses is 0.0244 m/s².
Answer:
5.88×10⁸ W
Explanation:
Power = change in energy / time
P = mgh / t
P = (m/t) gh
P = (1.2×10⁶ kg/s) (9.8 m/s²) (50.0 m)
P = 5.88×10⁸ W
Answer:
The inductor contains
loops
Explanation:
From the question we are told that
The capacitance of the capacitor is 
The resonance frequency is 
The diameter is 
The of the air-core inductor is 
The permeability of free space is 
Generally the inductance of this air-core inductor is mathematically represented as

This inductance can also be mathematically represented as

Where
is the angular speed mathematically given as

So

Now equating the both formulas for inductance

making N the subject of the formula


Substituting value
loops