Answer:
P = 16,000 kgm/s
Explanation:
<u><em>Given :</em></u>
Mass = m = 800 kg
Velocity = v = 72 km/hr = 20 m/s
<u><em>Required :</em></u>
Momentum = P = ?
<u><em>Formula:</em></u>
P = mv
<u><em>Solution:</em></u>
P = (800)(20)
P = 16,000 kgm/s
Answer:
F = 339.23 N
Explanation:
Weight of a car, W = 1050 N
Initial velocity, u = 0
Final velocity, v = 42 m/s
Time, t = 13 s
The weight of an object is given by :
W = mg
g is the acceleration due to gravity
The force acting on car is :
So, the force acting on the car is 339.23 N.
Answer: vl = 2.75 m/s vt = 1.5 m/s
Explanation:
If we assume that no external forces act during the collision, total momentum must be conserved.
If both cars are identical and also the drivers have the same mass, we can write the following:
m (vi1 + vi2) = m (vf1 + vf2) (1)
The sum of the initial speeds must be equal to the sum of the final ones.
If we are told that kinetic energy must be conserved also, simplifying, we can write:
vi1² + vi2² = vf1² + vf2² (2)
The only condition that satisfies (1) and (2) simultaneously is the one in which both masses exchange speeds, so we can write:
vf1 = vi2 and vf2 = vi1
If we call v1 to the speed of the leading car, and v2 to the trailing one, we can finally put the following:
vf1 = 2.75 m/s vf2 = 1.5 m/s
The answer is (A) the object must be at rest.
When all of the forces acting on an object balance, the net force is zero and hence the object will not move.
Yes, the direction might also change under some special circumstances.
