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3 years ago

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A car on a roller coaster loaded with passengers has a mass of 2.0 x 10^3 kg. At the lowest point of the the track, the radius o

f curvature is 24 m and the roller coaster car has a tangential speed of 17 m/s

1 answer:

mart [117]3 years ago

6 0

Answer:

here is my work

Explanation:

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A system of two objects has ΔKtot = 6 J and ΔUint = -5 J. Part A How much work is done by interaction forces? Express your answe

Elina [12.6K]

A) +5 J

B) +1 J

Explanation:

A)

The internal forces (interaction forces) acting on a system do not change the mechanical energy (sum of potential and kinetic energy) of the system.

However, these forces are responsible for converting the energy from one form into another; the work done by these forces is equal to the amount of energy converted from one form into the other.

In this problem, we have:

$\Delta U=-5 J$ is the loss in potential energy of the system

$\Delta K=+6 J$ is the gain in kinetic energy of the system

By looking at these numbers, this means that the internal forces have converted 5 J of energy from potential energy into kinetic energy (while the additional +1 J missing is due to external forces, as explained in part B).

Therefore, the work done by internal forces is

W = +5 J

B)

First of all, we calculate the change in mechanical energy of the system.

The mechanical energy of a system is the sum of its kinetic energy (K) and its potential energy (U):

$E=K+U$

So, the change in mechanical energy is equal to the sum of the changes of kinetic energy and the changes of potential energy:

$\Delta E= \Delta K + \Delta U$

In this problem:

$\Delta K=+6 J$

$\Delta U=-5 J$

So, the change in mechanical energy is:

$\Delta E=+6+(-5)=+1 J$

According to the work-energy theorem, the work done by external forces on a system is equal to the change in mechanical energy of the system: therefore in this case, the work done by external forces is

$W=\Delta E=+1 J$

5 0

4 years ago

The average energy per unit time per unit area that reaches the upper atmosphere of the Earth from the Sun, called the solar con

Lynna [10]

Answer: 5.34 MJ

Explanation: The window is a rectangle with area:

A = 1.1(1.5)

A = 1.65 m²

We know that only 0.9 kW/m² reaches Earth so:

P = $0.9\frac{kW}{m^{2}}(1.65)m^{2}$

P = 1.485 x 10³ W

Watts is an unit of Power and it can also be written as J/s.

An hour has 3600s or 3.6 x 10³s, so:

E = 1.485 x 10³ $\frac{J}{s}$ (3.6 x 10³s)

E = 5.346 x 10⁶ J

Mega is equal to 10⁶, then:

E = 5.35 MJ

A 1.1 m by 1.5 m window collects, during 1 hour of daylight, 5.35 MJ

8 0

3 years ago

A car traveling at 60 km/h will skid 30 m when its brakes are locked. if the same care is traveling at 180 km/h, what will be th

Flauer [41]

The first car travels at 60km/h and skid at 30m away from the starting point while another car is also traveling at 180km/h. Now, we need to solve for the skidding distance.
We assigned variables such as:
V1=60km/h
V2=180km/h
Skid1=30m
Skid2=?
We solve this by ratio and proportion method such as shown below:
V1/V2=skid1/skid2
60/180=30/skid2
skid2=(30*180)/60
skid2=90meters

Th answer is 90 meters.

3 0

3 years ago

Read 2 more answers

The field around a solenoid is similar to the field around a bar magnet.<br><br> true or false?

OlgaM077 [116]

The answer would be true :)

8 0

3 years ago

Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the first battery is twice the vol

Alex_Xolod [135]

Answer:

$v_1 = 12 volts$

$v_2 = 6 volts$

$v_3 = 36 volts$

Explanation:

As we know that all the batteries are in series

so the net voltage of all three batteries is given as

$V = v_1 + v_2 + v_3$

now we know that

$v_1 = 2v_2$

$v_1 = \frac{1}{3}v_3$

now plug in all the values in it

$54 = v_1 + \frac{v_1}{2} + 3v_1$

$54 = 4.5 v_1$

$v_1 = 12 volts$

now we have

$v_2 = 6 volts$

$v_3 = 36 volts$

3 0

3 years ago