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lara31 [8.8K]
3 years ago
15

I have a question, it concerns hydrostatic buoyancy and Archimedes' law.

Physics
1 answer:
saw5 [17]3 years ago
4 0

Answer: the lvl wud remain the same

Explanation: as per Archimedes Principle, the weight of the water displaced by the object is equal to the weight of the object. When the ship initially went into the pool, it wud hv displaced some water. When the anchor is dropped, the level does not change coz the anchor was already in the ship and no extra weight has been added, so the weight of the anchor has already been accounted for in the first place when the ship was first placed in the pool

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A van is traveling with an initial velocity of 12 m/s. The driver takes a time of 45 seconds to speed up to a velocity of 20 m/s
Rufina [12.5K]
  • Initial velocity=u=12m/s
  • Final velocity=v=20m/s
  • Time=t=45s

\\ \rm\hookrightarrow Acceleration=\dfrac{v-u}{t}

\\ \rm\hookrightarrow Acceleration=\dfrac{20-12}{45}

\\ \rm\hookrightarrow Acceleration=\dfrac{8}{45}

\\ \rm\hookrightarrow Acceleration=0.1m/s^2

Now

  • Distance=s

\\ \rm\hookrightarrow v^2-u^2=2as

\\ \rm\hookrightarrow (20)^2-12^2=2(0.1)s

\\ \rm\hookrightarrow 400-144=0.2s

\\ \rm\hookrightarrow 256=0.2s

\\ \rm\hookrightarrow s=\dfrac{256}{0.2}

\\ \rm\hookrightarrow s=1280m

4 0
3 years ago
Explain at least three ways trees assist in keeping high water quality?
swat32
<span>Tree's are vital to the eco-system, they clean the air of co2 which is important for the air and water. Tree's also stop erosion and that is an important step in keeping our water clean. Tree's filter water up through the soil with their extensive root system, making for clean water.</span>
3 0
3 years ago
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The object of badminton is to hit the birdie or "shuttlecock" over the net and onto to court to score how many points to win gam
xxTIMURxx [149]

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3 years ago
An experiment is done to compare the initial speed of projectiles fired from high-performance catapults. The catapults are place
anzhelika [568]

Answer:1.084

Explanation:

Given

mass of Pendulum M=10 kg

mass of bullet m=5.5 gm

velocity of bullet u

After collision let say velocity is v

conserving momentum we get

mu=(M+m)v

v=\frac{m}{M+m}\times u

Conserving Energy for Pendulum

Kinetic Energy=Potential Energy

\frac{(M+m)v^2}{2}=(M+m)gh

here h=L(1-\cos \theta ) from diagram

therefore

v=\sqrt{2gL(1-\cos \theta )}

initial velocity in terms of v

u=\frac{M+m}{m}\times \sqrt{2gL(1-\cos \theta )}

For first case \theta =6.8^{\circ}

u_1=\frac{M+m_1}{m_1}\times \sqrt{2gL(1-\cos 6.8)}

for second case \theta =11.4^{\circ}

u_2=\frac{M+m_2}{m_2}\times \sqrt{2gL(1-\cos 11.4)}

Therefore \frac{u_1}{u_2}=\frac{\frac{M+m_1}{m_1}\times \sqrt{2gL(1-\cos 6.8)}}{\frac{M+m_2}{m_2}\times \sqrt{2gL(1-\cos 11.4)}}

\frac{u_1}{u_2}=\frac{1819.181\times 0.0838}{1001\times 0.1404}

\frac{u_1}{u_2}=1.084

i.e.\frac{v_1}{v_2}=1.084

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