The change of the copper temperature if a 0.6g piece of copper is heated and fashioned into a bracelet with 62,100 J amount of energy transferred is 265.4°C.
<h3>How to calculate change in temperature?</h3>
The change in temperature of a metallic substance in a calorimetry experiment can be calculated using the following formula:
Q = mc∆T
Where;
- Q = quantity of heat absorbed or released
- m = mass of copper
- ∆T = change in temperature
- c = specific heat capacity
According to this question, a 0.6g piece of copper is heated and fashioned into a bracelet The amount of energy transferred by heat to the copper is 62,100 J.
62100 = 0.6 × 390 × ∆T
62100 = 234∆T
∆T = 62100/234
∆T = 265.4°C
Therefore, the change of the copper temperature if a 0.6g piece of copper is heated and fashioned into a bracelet with 62,100 J amount of energy transferred is 265.4°C.
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Answer:
a)![p=1.89x10^{-27}kg.m.s^{-1}](https://tex.z-dn.net/?f=p%3D1.89x10%5E%7B-27%7Dkg.m.s%5E%7B-1%7D)
b)![v=0.565\frac{m}{s}](https://tex.z-dn.net/?f=v%3D0.565%5Cfrac%7Bm%7D%7Bs%7D)
Explanation:
First, we need to obtain the linear momentum of the photons of wavelength 350nm.
We are going to use the following formula:
![\lambda=\frac{h}{p}\\Where:\\\lambda=wavelength\\h=placnk's\_constant\\p=Linear\_momentum](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7Bh%7D%7Bp%7D%5C%5CWhere%3A%5C%5C%5Clambda%3Dwavelength%5C%5Ch%3Dplacnk%27s%5C_constant%5C%5Cp%3DLinear%5C_momentum)
So the linear momentum is given by:
![p=\frac{h}{\lambda}\\\\p=\frac{6.626x10^{-34}J.s}{350x10^{-9}m}\\\\p=1.89x10^{-27}kg.m.s^{-1}](https://tex.z-dn.net/?f=p%3D%5Cfrac%7Bh%7D%7B%5Clambda%7D%5C%5C%5C%5Cp%3D%5Cfrac%7B6.626x10%5E%7B-34%7DJ.s%7D%7B350x10%5E%7B-9%7Dm%7D%5C%5C%5C%5Cp%3D1.89x10%5E%7B-27%7Dkg.m.s%5E%7B-1%7D)
Having the linear momentum of the photon, we can calculate the speed of the hydrogen molecule to have the same momentum, we can use the classic formula for that:
![p=m.v](https://tex.z-dn.net/?f=p%3Dm.v)
![where:\\m=mass\\v=speed\\p=linear\_momentum](https://tex.z-dn.net/?f=where%3A%5C%5Cm%3Dmass%5C%5Cv%3Dspeed%5C%5Cp%3Dlinear%5C_momentum)
The mass of the hydrogen molecule is given by:
![m=2*(1.0078x10^{-3}\frac{kg}{mol}})x\frac{1}{6.022x10^{23}mol}](https://tex.z-dn.net/?f=m%3D2%2A%281.0078x10%5E%7B-3%7D%5Cfrac%7Bkg%7D%7Bmol%7D%7D%29x%5Cfrac%7B1%7D%7B6.022x10%5E%7B23%7Dmol%7D)
![3.35x10^{-27}kg](https://tex.z-dn.net/?f=3.35x10%5E%7B-27%7Dkg)
What we've done here is to use the molecular weight of the hydrogen, and covert it kilograms, we had to multiply by two because the hydrogen molecule is found in pairs.
so:
![v=\frac{p}{m}\\\\v=\frac{1.89x10^{-27}kg.m.s^{-1}}{3.35x10^{-27}kg}\\\\v=0.565\frac{m}{s}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bp%7D%7Bm%7D%5C%5C%5C%5Cv%3D%5Cfrac%7B1.89x10%5E%7B-27%7Dkg.m.s%5E%7B-1%7D%7D%7B3.35x10%5E%7B-27%7Dkg%7D%5C%5C%5C%5Cv%3D0.565%5Cfrac%7Bm%7D%7Bs%7D)
Answer:
![I_2 = 3.16 I_1](https://tex.z-dn.net/?f=I_2%20%3D%203.16%20I_1)
Explanation:
given,
Intensity radiated by black body= I₁
room temperature = 300 K
Intensity radiated, I₂ = ?
At temperature = T₂ = 400 K
now,
Intensity of radiation, I = σ T⁴
now,
![\dfrac{I_1}{I_2}=\dfrac{T_1^4}{T_2^4}](https://tex.z-dn.net/?f=%5Cdfrac%7BI_1%7D%7BI_2%7D%3D%5Cdfrac%7BT_1%5E4%7D%7BT_2%5E4%7D)
![\dfrac{I_2}{I_1}=\dfrac{T_2^4}{T_1^4}](https://tex.z-dn.net/?f=%5Cdfrac%7BI_2%7D%7BI_1%7D%3D%5Cdfrac%7BT_2%5E4%7D%7BT_1%5E4%7D)
![I_2=I_1\dfrac{T_2^4}{T_1^4}](https://tex.z-dn.net/?f=I_2%3DI_1%5Cdfrac%7BT_2%5E4%7D%7BT_1%5E4%7D)
![I_2=I_1\dfrac{400^4}{300^4}](https://tex.z-dn.net/?f=I_2%3DI_1%5Cdfrac%7B400%5E4%7D%7B300%5E4%7D)
![I_2 = 3.16 I_1](https://tex.z-dn.net/?f=I_2%20%3D%203.16%20I_1)
hence, Radiation Intensity at 400 K is equal to I₂ = 3.16 I₁
Given: Weight W = 100 lbs convert to Kg = 45.36 Kg
Height h = 8 Ft convert to meter = 2.44 m
Time t =10 s
Required: Power output
Formula: P = W/t Work = Force x distance or Work = mgh
P = mgh/t
P = (45.36 Kg)(9.8 m/s²)(2.44 m)/10 s
P = 108.46 J/s
P = 0.15 Horsepower
Answer:
Kinetic energy is energy possessed by an object in motion. The earth revolving around the sun, you walking down the street, and molecules moving in space all have kinetic energy. Potential energy is energy an object has because of its position relative to some other object.
Explanation: