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Arturiano [62]
3 years ago
12

What part of an atom determines if it will combine or break apart from other substances?

Chemistry
1 answer:
Anni [7]3 years ago
8 0

Electron is the correct answer :D

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A sample of an ideal gas has a volume of 2.21 L at 282 K and 1.03 atm. Calculate the pressure when the volume is 1.84 L
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Answer:

1.33 atm

Explanation:

use general gas equation P1 V1/ T1 = P2 V2/ T2

rearrange and make P2 the subject then solve,it should give you 1.33 atm

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All matter has thermal energy because atoms are constantly
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The atoms are constantly in motion
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Which energy level has the most energy available to it?<br> 4<br> 3<br> 2<br> 1
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Tropic levels have most energy
8 0
3 years ago
Name NaCl; is it a) molecular b) ionic c) elemental d) strong electrolyte, e) weak electrolyte f) non-electrolyte g) acid h) bas
ioda

Answer:

i)salt

Explanation:

NaCl is a neutral salt formed by reacting a strong acid HCl and a strong base NaOH. It is also ionic in nature.

It is also called common salt or table salt as it is used as edible in daily our life.

4 0
3 years ago
For the reaction Na2CO3+Ca(NO3)2⟶CaCO3+2NaNO3 how many grams of calcium carbonate, CaCO3, are produced from 79.3 g of sodium car
Alexus [3.1K]

Answer:

74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.

Explanation:

The balanced reaction is:

Na₂CO₃ + Ca(NO₃)₂ ⟶ CaCO₃ + 2 NaNO₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:

  • Na₂CO₃: 1 mole
  • Ca(NO₃)₂: 1 mole
  • CaCO₃: 1 mole
  • NaNO₃: 2 mole

Being the molar mass of the compounds:

  • Na₂CO₃: 106 g/mole
  • Ca(NO₃)₂: 164 g/mole  
  • CaCO₃: 100 g/mole
  • NaNO₃: 85 g/mole

then by stoichiometry the following quantities of mass participate in the reaction:

  • Na₂CO₃: 1 mole* 106 g/mole= 106 g
  • Ca(NO₃)₂: 1 mole* 164 g/mole= 164 g
  • CaCO₃: 1 mole* 100 g/mole= 100 g
  • NaNO₃: 2 mole* 85 g/mole= 170 g

You can apply the following rule of three: if by stoichiometry 106 grams of Na₂CO₃ produce 100 grams of  CaCO₃, 79.3 grams of Na₂CO₃ produce how much mass of  CaCO₃?

mass of CaCO_{3} =\frac{79.3 grams of Na_{2} CO_{3} *100 grams of of CaCO_{3}}{106 grams of Na_{2} CO_{3}}

mass of CaCO₃= 74.81 grams

<u><em>74.81 grams of calcium carbonate are produced from 79.3 g of sodium carbonate.</em></u>

6 0
3 years ago
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