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Citrus2011 [14]
3 years ago
7

Which of the following pairs of elements are most likely to form an ionic bond?

Chemistry
1 answer:
gregori [183]3 years ago
5 0

Answer:

Ionic bonds ussally form with a metal, and a non metel elements, so the answer would most likley be B.

Explanation:

hope I could help

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The reaction of an acid and a base will always produce what kind of salt?
Illusion [34]

Answer:

the answer of the question is c

7 0
2 years ago
Compute the number of grams(g) of lead in 22.5 moles of lead.
iogann1982 [59]

Answer:

4662 in grams

Explanation:

hope this helps :).

7 0
2 years ago
Will give lots of points if answered correctly. Determine the kb for chloroform when 0.793 moles of solute in 0.758 kg changes t
Liono4ka [1.6K]

Answer: The value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

Explanation:

Given: Moles of solute = 0.793 mol

Mass of solvent = 0.758

\Delta T_{b} = 3.80^{o}C

As molality is the number of moles of solute present in kg of solvent. Hence, molality of given solution is calculated as follows.

Molality = \frac{no. of moles}{mass of solvent (in kg)}\\= \frac{0.793 mol}{0.758 kg}\\= 1.05 m

Now, the values of K_b is calculated as follows.

\Delta T_{b} = i\times K_{b} \times m

where,

i = Van't Hoff factor = 1 (for chloroform)

m = molality

K_{b} = molal boiling point elevation constant

Substitute the values into above formula as follows.

\Delta T_{b} = i\times K_{b} \times m\\3.80^{o}C = 1 \times K_{b} \times 1.05 m\\K_{b} = 3.62^{o}C/m

Thus, we can conclude that the value of K_{b} for chloroform is 3.62^{o}C/m when 0.793 moles of solute in 0.758 kg changes the boiling point by 3.80 °C.

7 0
3 years ago
Plz help ill give brainlist‼️‼️How do molecules become substances???
almond37 [142]
This is what I found!!! I hope this helps!!!!

8 0
2 years ago
Read 2 more answers
___ Is a type of wave that can travel through empty space to transfer energy from place to place
Mandarinka [93]
Where are the choices?
8 0
2 years ago
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