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tigry1 [53]
3 years ago
15

The flash unit in a camera uses a special circuit to "step up" the 3.0 V from the batteries to 360 V , which charges a capacitor

. The capacitor is then discharged through a flashlamp. The discharge takes 12 μs , and the average power dissipated in the flashlamp is 1.0×105 W .What is the capacitance of the capacitor? use 2 sigfigsI have tried 0.27 F and 0.26 F but so far both are wrong on mastering physics.
Physics
1 answer:
aksik [14]3 years ago
7 0

Answer:

The capacitance of the capacitor is 1.85*10^{-5}F

Explanation:

To solve this exercise it is necessary to apply the concepts related to Power and energy stored in a capacitor.

By definition we know that power is represented as

P = \frac{E}{t}

Where,

E= Energy

t = time

Solving to find the Energy we have,

E = P*t

Our values are:

P = 1*10^5W

t = 12*10^{-6}s

Then,

E= (1*10^5)(12*10^{-6})

E = 1.2J

With the energy found we can know calculate the Capacitance in a capacitor through the energy for capacitor equation, that is

E=\frac{1}{2}CV^2

Solving for C=

C = \frac{1}{2}\frac{E}{V^2}

C = 2\frac{1.2}{(360^2-3^2)}

C = 1.85*10^{-5}F

Therefore the capacitance of the capacitor is 1.85*10^{-5}F

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