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Thepotemich [5.8K]
2 years ago
11

Which pair of quantities represent scalar quantities, and how are they different from vector quantities?

Physics
1 answer:
Ann [662]2 years ago
8 0

D.

They don't have directions.

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Morgarella [4.7K]
The force and motion
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3 years ago
You are at the controls of a particle accelerator, sending a beam of 2.10×107 m/s protons (mass m) at a gas target of an unknown
Kipish [7]

Answer:

a

The mass is  m_2 =21.75*10^{-27} \ kg

b

The velocity is  v_2 = 3.0*10^{6} m/s

Explanation:

From the question we are told that

     The speed of the protons is  u_1 =  2.10*10^{7} m/s

     The mass of the protons is  m

     The speed of the rebounding protons are v_1 =  -1.80 * 10^{7} \ m/s

The negative sign shows that it is moving in the opposite direction

     

Now according to the law of energy conservation mass of one nucleus of the unknown element. is mathematically represented as

        m_2 = [\frac{u_1 -v_1}{u_1 + v_1} ] m_1

Where m_1 is the mass of a single proton

          So substituting values

       m_2 = \frac{2.10 *10^{7} - (-1.80 *10^{7})} {(2.10 *10^7) + (-1.80 *10^{7})} m_1

        m_2 =13 m_1

The mass of on proton is  m_1 = 1.673 * 10^{-27} \ kg

So     m_2 =13 ( 1.673 * 10^{-27} )

        m_2 =21.75*10^{-27} \ kg

Now according to the law of linear momentum conservation the speed of the unknown nucleus immediately after such a collision is mathematically evaluated as

      m_1 u_1 + m_2u_2 = m_1 v_1 + m_2v_2

Now  u_2 because before collision the the nucleus was at rest

So

        m_1 u_1 =  m_1 v_1 + m_2v_2

=>    v_2 =  \frac{m_1(u_1 -v_1)}{m_2}

Recall that m_2 =13 m_1

So

       v_2 =  \frac{m_1(u_1 -v_1)}{13m_1}

=>         v_2 =  \frac{(u_1 -v_1)}{13}

substituting values

              v_2 =  \frac{( 2.10*10^{7} -(-1.80 *10^{7}))}{13}

              v_2 = 3.0*10^{6} m/s

   

7 0
3 years ago
A car has a mass of 900 kilograms and has a force of 4500 to the left what is the acceleration
pychu [463]

Answer: A- A truck has a mass of 900 kilograms.

If the velocity of the truck is 20 m/s, what is its momentum?

1- 180000 kg·m/s

2-0 kg·m/s

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4-18000 kg·m/s

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Justin is riding his bike up Dunmore Hill. The effort force from his feet on his pedals is 1160N.
Schach [20]

Explanation:

the answer is 1835N that how best I can help

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Two cyclists start at the same point, but travel along two straight streets in different directions. if they continue, how many
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Since they are travelling on two different straight directions, therefore their paths will NEVER cross again. This because straight lines will keep on going forever on the same direction therefore there is 0 possibility for two straight lines to paths cross again.

 

Answer:

<span>zero or never</span>

8 0
3 years ago
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