Answer:
Option 4
Step-by-step explanation:
=> 
Combining like terms
=> 
=> 
Answer:
The answer would be 22/12 or 1 and 11/12
Step-by-step explanation:
1/2+2/3+3/4
First get common denominators so you have a denominator of 12 so 6/12+8/12+9/12
Add those together and you get 23/12 but you have to subtract one because that's what the problem says so you get 22/12
Answer:
<u>Option C. It is zero</u>
Step-by-step explanation:
The graph represents a quadratic equation
The quadratic equation has the form ⇒a x² + b x + c
The discriminant of the quadratic equation is D = b² - 4ac
From the discriminant of the quadratic equation, we can know the type of roots of the quadratic equation.
- If D > 0 ⇒ Two real roots.
- If D = 0 ⇒ one real roots
- If D < 0 ⇒ Two imaginary roots.
The roots of the quadratic equation are the x-intercepts of the function.
As shown at the figure, the quadratic equation has only one point of intersection with the x-axis
So, the function has only one root ⇒ D = 0
So, the discriminant of the quadratic equation = 0
<u>The answer is option C. It is zero</u>
Answer:
A=3x^2 -14x -5
Step-by-step explanation:
(x-5)(3x+1)
3x^2 +x -15x -5
3x^2 -14x -5
Let us make a list of all the details we have
We are given
The cost of each solid chocolate truffle = s
The cost of each cream centre chocolate truffle = c
The cos to each chocolate truffle with nuts = n
The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25
That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)
The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75
That is 10s+5c+10n = $68.75
The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00
That is 12s+12n=$66.00
Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.
