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VMariaS [17]
3 years ago
6

Liquids diffuse more slowly than gases because

Chemistry
1 answer:
aliya0001 [1]3 years ago
3 0
Gas<span> molecules </span>diffuse more<span> quickly </span>than<span> liquid and solid molecules </span>because<span> there is</span>more<span> free space between </span>gas<span> molecules, which gives them </span>more<span> room to move. This causes the molecules to bounce against each other and increases the rate of diffusion. The molecules in liquid are much closer together </span>than<span> those in </span>gas<span>.</span>
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Given the following equation, how many moles of Fe2O3 can be produced from 6.4 moles O2?
scoundrel [369]

Answer:

4.3 moles of Fe2O3

Explanation:

The calculations are shown in the picture.

5 0
3 years ago
if 28.5 g of calcium hydroxide is dissolved in enough water to make 185g of solution what is the percent by mass of calcium hydr
DENIUS [597]

The percent by mass of calcium hydroxide in the solution : 15.41%

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Mass of solute (Ca(OH₂-Calcium hydroxide) : 28.5

Mass of solution = 185 g

\tt \%mass=\dfrac{mass~solute}{mass~solution}\times 100\%\\\\\%mass=\dfrac{28.5~g}{185~g}\times 100\%\\\\\%mass=15.41\%

6 0
3 years ago
For each reaction, find the value of ΔSo. Report the value with the appropriate sign. (a) 3 NO2(g) + H2O(l) → 2 HNO3(l) + NO(g)
aev [14]

Answer:

ΔS° = -268.13 J/K

Explanation:

Let's consider the following balanced equation.

3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)

We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:

ΔS° = ∑np.Sp° - ∑nr.Sr°

where,

ni are the moles of reactants and products

Si are the standard molar entropies of reactants and products

ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]

ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]

ΔS° = -268.13 J/K

7 0
3 years ago
I need help with both questions
a_sh-v [17]

Answer:

not sure about 6 but 7 should be c

Explanation:

..

6 0
3 years ago
How many grams of fluorine are needed to react with 8.5g of phosphorus?
love history [14]

Step 1: write the equation:

                                          P₄(s) + 6F₂(g) → 4PF₃(g) 


Step 2: Molar mass of P₄ = 30.97 g/mol × 4 = 123.88 g/mol


Step 3: Number of moles of phosphorus

                                                    n = m/M 

                                                    n = 8.5 g/123.88g/mol

                                                    n = 0.07 moles


Step 4: 0.07 × 12 = 0.84 moles of fluorine.

Fluorine is diatomic gas so we multiplied the number of moles by 12.


Step 5: To find the mass of fluorine we multiply the number of moles with the molar mass.

                            Mass of fluorine = 0.84 ×  228 

                                                        = 191.52 grams.

4 0
3 years ago
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