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seropon [69]
3 years ago
14

It takes a pulse of light 35 microseconds to travel down a 5.0 km length of fiber optic cable. How fast does light move through

the cable (in m/s)?
Physics
1 answer:
kogti [31]3 years ago
7 0
It takes 7 microseconds for each km
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A straight wire carrying a 3.30-A current is placed in a uniform magnetic field of magnitude 0.272 T directed perpendicular to t
stira [4]

Answer:

F = 0.114 N

Explanation:

a) The magnetic force is given by the equations

    F = q v x B = I Lx B

the bold incate vector.  This equation can be used in the form of magnitude and find the direction separately with the rule of the right hand

    F = i L B sin θ

Where θ is the angle between the direction (L) and the magnetic field, if the two are perpendicular sin 90 = 1

Let's calculate

    F = 3.30 0.127 0.272

    F = 0.114 N

b) to know the direction of the magnetized field we must know the direction of B and L, but in the problem they tell us that they are perpendicular, but not the direction of each

6 0
3 years ago
Kepler modified Copernicus's model of the universe by proposing that the A. Planets follow a circular orbit around the sun. B. P
lisabon 2012 [21]

Answer:

I believe the answer is B, the paths of the planets follow an elliptical orbit around the sun.

5 0
4 years ago
Read 2 more answers
What is the current in a circuit with a 4.5 V battery and a 9 Ω resistor?
horsena [70]

Answer:

V=I×R

<em>4</em><em>.</em><em>5</em><em> </em><em>=</em><em> </em><em>I×</em><em>9</em>

<em> </em><em> </em><em> </em><em>I</em><em>.</em><em> </em><em>=</em><em> </em><em>4</em><em>.</em><em>5</em><em>/</em><em>9</em>

<em> </em><em> </em><em> </em><em>I</em><em>. </em><em>=</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>A</em>

<em>curre</em><em>nt</em><em> </em><em>is</em><em> </em><em>0</em><em>.</em><em>5</em><em> </em><em>A</em>

3 0
3 years ago
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A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the
natka813 [3]

Answer:

Speed of the satellite V = 6.991 × 10³ m/s

Explanation:

Given:

Force F = 3,000N

Mass of  satellite m = 500 kg

Mass of earth M = 5.97 × 10²⁴

Gravitational force G = 6.67 × 10⁻¹¹

Find:

Speed of the satellite.

Computation:

Radius r = √[GMm / F]

Radius r = √[(6.67 × 10⁻¹¹ )(5.97 × 10²⁴)(500) / (3,000)

Radius r = 8.146 × 10⁶ m

Speed of the satellite V = √rF / m

Speed of the satellite V = √(8.146 × 10⁶)(3,000) / 500

Speed of the satellite V = 6.991 × 10³ m/s

8 0
3 years ago
What is the wave speed of a 6 m wave with a frequency of 20 Hz?
andrew-mc [135]

Answer: Wave speed= frequency x wavelength

=20 x 3

=60 m/s

Explanation:

8 0
3 years ago
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