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arlik [135]
3 years ago
8

In practice, both the rivet itself (length, diameter) and the hole in which it is placed have tolerances. How do these affect th

e eventual joint strength? (5 points) Hint: Consider that riveting can be done in two quite different ways: (1) displacement-driven, i.e. the riveting press moves forward a certain stroke, irrespective of the force that it builds up, and (2) force-driven, i.e. the press moves forward until a certain force is reached, irrespective of the required stroke.
Physics
1 answer:
Nikolay [14]3 years ago
8 0

Answer:

The quality of a formed rivet is determined by the geometry from its formation of the river heat, and the extent to which the hole is filled up by the rivet.

Explanation:

The quality of a formed rivet is determined by the geometry from its formation of the river heat, and the extent to which the hole is filled up by the rivet. This helps determine the squeeze force, rivet length, rivet diameter tolerance, hole countersunk depth and hole diameter tolerance, plays a big role on the quality of rivet formed. When the tolerance of the hole it’s placed is smaller the grip from the river is stronger unlike when it’s loose.

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1. A DC-10 jumbo jet maintains an airspeed of 550 mph in a southwesterly direction. The velocity of the jet stream is a constant
Vladimir79 [104]

Answer:

The magnitude of actual velocity is <u>496.67 mph</u> and its direction is <u>51.54° with the x axis in the third quadrant</u>.

Explanation:

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Speed of jumbo jet in southwesterly direction (v_j) = 550 mph

Velocity of jet stream from west to east direction (v_s)=80\ mph

First let us draw a vectorial representation of the above velocity vectors.

Consider the south direction as negative y axis and west direction as negative x axis.

From the diagram,

The velocity of the jet can be represented as:

\vec{v_j}=-550\cos(45)\vec{i}+(-550\sin(45)\vec{j} )\\\\\vec{v_j}=-388.91\vec{i}-388.91\vec{j}\ mph

Similarly, the velocity of the stream is, \vec{v_s}=80\vec{i}

Now, the vector sum of the above two vectors gives the actual velocity of the aircraft. So, the resultant velocity is given as:

\vec{v}=\vec{v_j}+\vec{v_s}\\\\\vec{v}=-388.91\vec{i}-388.91\vec{j}+80\vec{i}\\\\\vec{v}=(-388.91+80)\vec{i}-388.91\vec{j}\\\\\vec{v}=(-308.91)\vec{i}-388.91\vec{j}

Now, magnitude is given as the square root of sum of the squares of the 'i' and 'j' components. So,

|\vec{v}|=\sqrt{(-308.91)^2+(-388.91)^2}\\\\|\vec{v}|=496.67\ mph

As the horizontal and vertical components of actual velocity negative, the resultant vector makes an angle \theta with the x axis in the third quadrant.

The direction is given as:

\theta=\tan^{-1}(\frac{v_y}{v_x})\\\\\theta=\tan^{-1}(\frac{-388.91}{-308.91})\\\\\theta=51.54\°(Third\ quadrant)

Therefore, the magnitude of actual velocity is 496.67 mph and its direction is 51.54° with the x axis in the third quadrant.

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