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arlik [135]
4 years ago
8

In practice, both the rivet itself (length, diameter) and the hole in which it is placed have tolerances. How do these affect th

e eventual joint strength? (5 points) Hint: Consider that riveting can be done in two quite different ways: (1) displacement-driven, i.e. the riveting press moves forward a certain stroke, irrespective of the force that it builds up, and (2) force-driven, i.e. the press moves forward until a certain force is reached, irrespective of the required stroke.
Physics
1 answer:
Nikolay [14]4 years ago
8 0

Answer:

The quality of a formed rivet is determined by the geometry from its formation of the river heat, and the extent to which the hole is filled up by the rivet.

Explanation:

The quality of a formed rivet is determined by the geometry from its formation of the river heat, and the extent to which the hole is filled up by the rivet. This helps determine the squeeze force, rivet length, rivet diameter tolerance, hole countersunk depth and hole diameter tolerance, plays a big role on the quality of rivet formed. When the tolerance of the hole it’s placed is smaller the grip from the river is stronger unlike when it’s loose.

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Gravity pushes against all objects, trying to crush it. What pushes against gravity in: a main sequence star, a white dwarf, a n
ololo11 [35]

Answer:

heat pressure, neutron degeneracy, electron degeneracy,nothing.

Explanation:

In main sequence star, gravity's inward pull is greatly balanced by the heat pressure. In the white dwarf, gravity is mainly balanced by the electron degeneracy pressure that arises from the fact that the electrons are fermions and they obey the Pauli's exclusion principle.  So there is no two electrons that have the same the four quantum numbers.

While in neutron star, the neutron degeneracy pressure obeys the Pauli's exclusion principle that gives rise to the degeneracy pressure and noting pushes against the gravity in the black hole. Therefore the correct option is the heat pressure, neutron degeneracy, electron degeneracy and nothing.

4 0
3 years ago
Determine the force Santa needs to accelerate a 25g model of the helpful guy in the blue polo shirt to 200,000.00 m/s2 assume th
liubo4ka [24]

Answer:

The force needed will be 5000[N]

Explanation:

Using the Newton's second law we have:

F = m*a\\where\\F = force [N]\\m = mass [kg]\\a= acceleration [m/s^2]\\Replacing we have\\F = 0.025[kg]*200000[m/s^2]\\F = 5000 [N]

4 0
3 years ago
A 108 kg clock initially at rest on a horizontal floor requires a 639 N horizontal force to set it in motion. After the clock is
labwork [276]

Answer:

\mu_s=0.60

Explanation:

It is given that,

Mass of the clock, m = 108 kg

Force acting on it when it is in motion, F=639\ N

After the clock is in motion, a horizontal force of 521 N keeps it moving with a constant velocity, F' = 521 N

It is assumed to find the coefficient of between the clock and the floor. The force of friction is given by :

F=\mu_smg

\mu_s=\dfrac{F}{mg}

\mu_s=\dfrac{639\ N}{108\ kg\times 9.8\ m/s^2}

\mu_s=0.60

So, the coefficient of static friction between the clock and the floor is 0.6. Hence, this is the required solution.

5 0
3 years ago
8. You push downward on a box with a force of 750 N. The box is on a flat horizontal surface for which the coefficient of static
natima [27]

Answer:

The mass of the heaviest box you will be able to move with this applied force = 61.4 kg

Explanation:

From the diagram attached, the forces acting on the box include the weight of the box, applied force on the box, normal reaction of the surface on the box and the Frictional force in the opposite direction to the applied force.

For the box to be able to move, the applied force must have a horizontal component that at least matches the Frictional force between the box and the surface. This is the force balance in the horizontal direction.

Resolving the applied force into horizontal and vertical components,

Fₓ = 750 cos 25° = 679.73 N

Fᵧ = 750 sin 25° = 316.96 N

Doing a force balance in the vertical axis,

N = (mg + 316.96)

Frictional force = μN = μ (mg + 316.96)

μ = 0.74, g = 9.8 m/s²

Frictional force = Fᵧ

μ (mg + 316.96) = 679.73

0.74(9.8m + 316.96) = 679.73

7.252m + 234.5504 = 679.73

7.252m = 679.73 - 234.5504 = 445.1796

m = (445.1796/7.252)

m = 61.4 kg

Hope this Helps!!!

6 0
3 years ago
How many significant numbers are in the measurement 589.040 newtons
Y_Kistochka [10]
There are 6 significant figures as trailing zeros count.
8 0
3 years ago
Read 2 more answers
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