Answer:
heat pressure, neutron degeneracy, electron degeneracy,nothing.
Explanation:
In main sequence star, gravity's inward pull is greatly balanced by the heat pressure. In the white dwarf, gravity is mainly balanced by the electron degeneracy pressure that arises from the fact that the electrons are fermions and they obey the Pauli's exclusion principle. So there is no two electrons that have the same the four quantum numbers.
While in neutron star, the neutron degeneracy pressure obeys the Pauli's exclusion principle that gives rise to the degeneracy pressure and noting pushes against the gravity in the black hole. Therefore the correct option is the heat pressure, neutron degeneracy, electron degeneracy and nothing.
Answer:
The force needed will be 5000[N]
Explanation:
Using the Newton's second law we have:
![F = m*a\\where\\F = force [N]\\m = mass [kg]\\a= acceleration [m/s^2]\\Replacing we have\\F = 0.025[kg]*200000[m/s^2]\\F = 5000 [N]](https://tex.z-dn.net/?f=F%20%3D%20m%2Aa%5C%5Cwhere%5C%5CF%20%3D%20force%20%5BN%5D%5C%5Cm%20%3D%20mass%20%5Bkg%5D%5C%5Ca%3D%20acceleration%20%5Bm%2Fs%5E2%5D%5C%5CReplacing%20we%20have%5C%5CF%20%3D%200.025%5Bkg%5D%2A200000%5Bm%2Fs%5E2%5D%5C%5CF%20%3D%205000%20%5BN%5D)
Answer:

Explanation:
It is given that,
Mass of the clock, m = 108 kg
Force acting on it when it is in motion, 
After the clock is in motion, a horizontal force of 521 N keeps it moving with a constant velocity, F' = 521 N
It is assumed to find the coefficient of between the clock and the floor. The force of friction is given by :




So, the coefficient of static friction between the clock and the floor is 0.6. Hence, this is the required solution.
Answer:
The mass of the heaviest box you will be able to move with this applied force = 61.4 kg
Explanation:
From the diagram attached, the forces acting on the box include the weight of the box, applied force on the box, normal reaction of the surface on the box and the Frictional force in the opposite direction to the applied force.
For the box to be able to move, the applied force must have a horizontal component that at least matches the Frictional force between the box and the surface. This is the force balance in the horizontal direction.
Resolving the applied force into horizontal and vertical components,
Fₓ = 750 cos 25° = 679.73 N
Fᵧ = 750 sin 25° = 316.96 N
Doing a force balance in the vertical axis,
N = (mg + 316.96)
Frictional force = μN = μ (mg + 316.96)
μ = 0.74, g = 9.8 m/s²
Frictional force = Fᵧ
μ (mg + 316.96) = 679.73
0.74(9.8m + 316.96) = 679.73
7.252m + 234.5504 = 679.73
7.252m = 679.73 - 234.5504 = 445.1796
m = (445.1796/7.252)
m = 61.4 kg
Hope this Helps!!!
There are 6 significant figures as trailing zeros count.