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timofeeve [1]
2 years ago
12

Archimedes supposedly was asked to determine whether a crown made for the king consisted of puregold. According to legend, he so

lved this problem by weighing the crown first in air and then in water. Suppose the scale read 7.84 N with the crown in air and 6.84 N when it was in water. What should Archimedes have told the king
Physics
1 answer:
DENIUS [597]2 years ago
4 0

Answer:

the crown was not made of pure gold

Explanation:

Mass of gold = weight in air/ g = 7.84N/10ms-2= 0.784 Kg or 0.8Kg

From Archimedes principle:

Upthrust= weight in air- weight in a fluid

Upthrust= volume × density × g

Note density of water = 1000kgm-3

7.84-6.84= V × 1000kgm-3×10ms-2

V= 1/10000= 1×10-4 m^3

Density = mass/ volume= 0.8/1×10-4

= 8×10^3 Kgm-3

But we know the density of gold to be 19.3 ×10^3 kgm-3

Hence the crown was not made of pure gold

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Answer:

m/s^2

Explanation:

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kgm/s^2 = kg × acceleration

where acceleration = Force ÷ mass

= kg m/s^2 ÷ kg

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3 years ago
A person is standing on a spring bathroom scale on the floor of an elevator which is moving up and slowing down at the rate of 2
Alinara [238K]

Answer:

923.44N

Explanation:

Obviously Fn cannot equal Fg since the elevator is moving up  

Where Fn is the force read on the scale

Fg is gravitational force=mg=77.6 x 9.8=760.48N

So we use this equation:  

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77.6 x 2.1 = Fn – 760.48

162.96N = Fn – 760.48N  

923.44 N = Fn

The answer is 923.44 N

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3 years ago
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A ball is kicked from the top of a building with a velocity of 50 m/s and lands 165 m away from the base of the building.
Nadusha1986 [10]

The height of the building is 53.4 m (projectile motion)

Explanation:

The motion of the ball is a projectile motion, so it follows a parabolic path which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction  

First of all, we consider the horizontal motion, which is a uniform motion at constant speed. The equation that gives the horizontal distance travelled is:

d=v_x t  

where:

v_x = 50 m/s is the horizontal velocity of the ball, which is constant since there are no forces in this direction

d = 165 m is the horizontal distance travelled by the ball

Solving for t, we find the time of flight:

t=\frac{d}{v_x}=\frac{165}{50}=3.3 s

Now we analyze the vertical motion: it is an accelerated motion, we can use the suvat equation

s=ut+\frac{1}{2}at^2  

where  

s is the vertical displacement, which is the height of the building

u = 0 is the initial vertical velocity of the ball

t = 3.3 s is the time of flight

a=g=9.8 m/s^2 is the acceleration of gravity  

Solving for s, we find the height of the building:

s=0+\frac{1}{2}(9.8)(3.3)^2=53.4 m

Learn more about projectile motion here:

brainly.com/question/8751410

#LearnwithBrainly

6 0
3 years ago
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