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kozerog [31]
3 years ago
14

How to protect the ozone layer?

Physics
1 answer:
Nady [450]3 years ago
3 0

Answer:

\huge{\purple{\underline{\underline{\bf{\pink{Answer}}}}}}

  1. we have to protect ozone layer because it is like blanket for earth . It protects the earth form uv rays that are coming from the sun

we have to take some preventive. measures like

  • Use ecofriendly things that Doesnot contain (cfc) . It is the major reason for ozone Deplition

Effects of uv rays

  • Uv rays are very harmful . If it directly comes in contact with human it cause skin cancer , eyes irritation etc.

Hope it helps.

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Musicians can use beats to tune their instruments. One flute is properly tuned and plays the musical note A at exactly 440 Hz. A
kodGreya [7K]

Answer:

439 Hz

Explanation:

f_1 = Frequency of first wave = 440 Hz

F = Beat frequency = 1 Hz

f_2 = Frequency of the instrument

The beat frequency is the difference of the two waves which are interacting with each other

F=f_1-f_2\\\Rightarrow 1=440-f_2\\\Rightarrow f_2=440-1\\\Rightarrow f_2=439\ Hz

The frequency of the instrument is 439 Hz

5 0
3 years ago
Can someone help me with 45a-g and 46?
LUCKY_DIMON [66]

Idk but it must be hard tho

7 0
3 years ago
Answer pls will give 20 points per person
LuckyWell [14K]

Answer: question 1 is b I believe

Explanation:

every action has an opposite reaction

7 0
3 years ago
Read 2 more answers
What is the other main factor used to determine climate
Scorpion4ik [409]
Temperature & amount

Hope I helped! ( Smiles ) 
8 0
4 years ago
Read 2 more answers
At an outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 25 cm on a spring with a spring con
KiRa [710]

Answer:

0.11m/s

Explanation:

To solve the exercise it is necessary to apply the concepts related to the conservation of both: kinetic and spring energy(Elastic potential energy), in this way

Kinetic Energy = Elastic potential energy

KE = SE

\frac{1}{2}mv^2 = \frac{1}{2}kX^2

Where,

m=mass

v=velocity

k=spring constant

x=amount of compression

Re-arrange the equation to find the velocity we have,

v^2 = \frac{kX^2}{m}

v^2 = \frac{10(0.25)^2}{50}

v = \sqrt{0.0125}

v = 0.11m/s

Therefore the maximum speed of the bananas is 0.11m/s

8 0
3 years ago
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