Answer:
The electric force will be 0 N
Explanation:
From the question we are told that
The magnitude of the charge is 
Generally from Coulombs law the electric force between two charges is mathematically represented as
Here r is the distance of separation between that two charges.
Now from the question we are told that the charge is far away from any other charge hence we can say that the distance between the charge and any other charge is 
So
=> 
Hence the electric force will be 0 N
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Answer:
1: a measuring instruments the students should use for time is a stopwatch
2: a measuring instruments the students should use for distance is a measuring tape
Explanation:
pls mark brainliest
Answer:
17.5
or
1.1 g/min
I know it's one of these, try getting a second opinion
For this problem, we use the derived equations for rectilinear motion at constant acceleration. The equations used for this problem are:
a = (v - v₀)/t
2ax = v² - v₀²
where
a is the acceleration
x is the distance
v is the final velocity
v₀ is the initial velocity
t is the time
The solution is as follows;
a = (60mph - 30 mph)/(3 s * 1 h/3600 s)
a = 36,000 mph²
2(36,000 mph²)(x) = 60² - 30²
Solving for x,
x = 0.0375 miles
