Answer:
A) probability that at least x of them will require repairs is less than 0.5 is 4
Step-by-step explanation:
sample size, n = 20
p = success probability of toaster = 0.2
q = failure probability of toaster =1- p = 1- 0.2 =0.8
mean, , μ = n * p = 20 * 0.2 = 4
standard deviation, 
a) the probability that at least some of them require repairs < 0.5.
for
value of z = 0
we know 
from z table
X = 4
B) SECOND PART IS INCOMPLETE { DATA IS INCOMPLETE}
I am not entirely sure but the answer should be 6^8
Answer : 1 9/20
1st Step : Make common denominators
3/4 + 7/10 = 15/20 + 14/20
2nd Step : Add!
15/20 + 14/20 = 29/20
3rd Step : Simplify, make the fraction a mixed number
29/20 = 1 9/20
1 and 9/20 is your answer
Answer:
- 0.964
Step-by-step explanation:
Given that Coefficient of determination (R^2) = 0.93
Slope of regression line = - 5.26
The linear correlation Coefficient =?
The Coefficient of determination (R^2) is used to obtain the proportion of explained variance of the regression line. It is the square of the linear correlation Coefficient (R).
Hence. To obtain the linear correlation Coefficient (R) from the Coefficient of determination (R^2); we take the square root of R^2
Therefore,
R = √R^2
R = √0.93
R = 0.9643650
R = 0.964
However, since the value of the slope is negative, this depicts a negative relationship between the variables, hence R will also be negative ;
Therefore, R = - 0.964
9514 1404 393
Answer:
(c) 1.649
Step-by-step explanation:
For a lot of these summation problems it is worthwhile to learn to use a calculator or spreadsheet to do the arithmetic. Here, the ends of the intervals are 1 unit apart, so we only need to evaluate the function for integer values of x.
Almost any of these numerical integration methods involve some sort of weighted sum. For <em>trapezoidal</em> integration, the weights of all of the middle function values are 1. The weights of the first and last function values are 1/2. The weighted sum is multiplied by the interval width, which is 1 for this problem.
The area by trapezoidal integration is about 1.649 square units.
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In the attached, we have shown the calculation both by computing the area of each trapezoid (f1 does that), and by creating the weighted sum of function values.