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Triss [41]
3 years ago
11

Electricians are advised to wear rubber gloves while working on electric devices.give reason​

Physics
1 answer:
gayaneshka [121]3 years ago
7 0

Electricians are advised to wear rubber gloves to protect themselves from being shocked.

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A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance x from the 50
Rom4ik [11]

Answer:

x=0.01457 m

Explanation:

From parallel axis theorem

I=Icm+mh²

where h=x

The rotational inertia about its center of mass is

Icm=mL²/12

where L=1.0 m

Thus T=4.8s  we obtain

T=2\pi \sqrt{\frac{mL^{2}/12+mx^{2}  }{mgx} }\\ T=2\pi \sqrt{\frac{L^{2} }{12gx}+x/g }\\ T^{2}=4\pi^{2}(\frac{L^{2} }{12gx}+x/g )/x\\ T^{2}x=\frac{\pi^{2} L^{2} }{3g}+(\frac{4\pi^{2} }{g})x^{2}\\   0=(\frac{4\pi^{2}  }{g} )x^{2}-(T^{2} )x+(\frac{\pi^{2}L^{2}   }{3g} )\\ 4.03x^{2}-23.04x+0.335=0

After Solving this quadratic we get

x₁=5.702 m

x₂=0.01457 m

One of the solution is an impossible value for x (x=5.70m is greater than L)

So we choose the other one

x=0.01457 m

3 0
4 years ago
Balanced or Unbalanced?
Galina-37 [17]

Unbalanced because if it is pushing then stopping, that means that it is unbalanced.

6 0
3 years ago
according to a rule-of-thumb, every 5 seconds, between a lightning flash and the following thunder gives the distance to the fla
jenyasd209 [6]
Given the speed of the sound in the problem which is 1 mile per 5 seconds. 

The speed is calculated by:

Speed = distance/time = (1mi/5s) (1610 m/1mi) = 300 m/s

Note that only 1 significant figure is given which is 5 second and so only 1 significant figure is justified in the result. The speed of sound is 343 m/s. therefore the rule of thumb is fairly close.
3 0
3 years ago
State characteristics of the images formed by pin - hole camera​
Leokris [45]

Answer:

Real image

Explanation:

The picture is real, but it is reversed and tiny. An picture generated by a pinhole camera has certain features. As compared item, the image created by a pinhole camera is normally pretty small and looks reversed both on the vertically and horizontally axis.

8 0
3 years ago
A car moving at 16.0 m/s, passes an observer while its horn is pressed. the velocity of sound is 343 m/s and the frequency of th
Arada [10]
We are asked to solve for the frequency heard when a car is coming towards the observer. The car is moving at 16 m/s and the velocity of the sound is 343 m/s where the car horns at 583 Hz. We will use Doppler's Effect formula in calculating the unknown frequency such that the solution is shown below:
Fl = (V + Vl) * Fs / (V - Vs)
FL = (343 + 0)*583 / (343 - 16)
FL = 611. 53 Hertz

The answer for the frequency of the observer is 611.53 hertz.
5 0
3 years ago
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