If a person want to move a <span>heavy box across the room, he must apply a force that is greater than starting frictional force acted on the heavy box in order to get the box in motion. the frictional force is equal to coefficient of friction times the normal force, and normal force is approximately the weight of the object. so the force that must be applied must be greater than the wieght of the object.</span>
8 because of the amount of calcium in the equator of the state Minnesota
but the points are only 25
Answer:
1.147 %
Explanation:
= Density of mercury = 
g = Acceleration due to gravity = 9.81 m/s²
h = Height of mercury = 8.69 m
Standard atmospheric pressure = 
6.55 mmHg converting to Pa

Dividing air pressure by the above value

The fraction of atmospheric pressure is 1.147 %