Answer:
intensity at a point on the circle at an angle of 4.45° from the center line is 1.77 W/m².
Explanation:
See attached picture.
Answer:
T = 2.4 + 2.4 = 4.8 [s]
Explanation:
In order to solve this problem, we must use the following kinematics equation and calculate the acceleration value.
![x=x_{o} +v_{o}*t+(\frac{1}{2})*a*t^{2}](https://tex.z-dn.net/?f=x%3Dx_%7Bo%7D%20%2Bv_%7Bo%7D%2At%2B%28%5Cfrac%7B1%7D%7B2%7D%29%2Aa%2At%5E%7B2%7D)
Vo = inital velocity = 0
x - xo = 15 [m]
t = time = 2.4 [s]
15 = 0.5*a*(2.4)^2
a = 5.208 [m/s^2]
We can use the same equation to find the time.
30 = 15 + 0.5*(5.208)*t^2
t = 2.4 [s]
T = 2.4 + 2.4 = 4.8 [s]
Velocity is speed plus direction, so an example of velocity would be a vehicle traveling at 75mph north. Velocity is a vector quantity because it describes both magnitude and direction.
Answer:
12°F
Explanation:
Calculation for how much subcooling is there in the condenser
Since the CONDENSING TEMPERATURE for 417.4 psig discharge pressure is 120 degrees (120°) which means that the amount of subcooling that is there in the condenser will be calculated using this formula
Amount of Condenser subcooling= Condensing Temperature discharge pressure -Condenser outlet temperature
Let plug in the formula
Amount of Condenser subcooling=120°-108f
Amount of Condenser subcooling=12°F
Therefore the amount of subcooling that is there in the condenser will be 12°F