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a_sh-v [17]
3 years ago
5

Question 4. Calculate the kinetic energy of a Year 11 pupil (mass 55Kg)

Physics
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

990 J

Explanation:

Kinetic energy is:

KE = ½ mv²

Given m = 55 kg and v = 6 m/s:

KE = ½ (55 kg) (6 m/s)²

KE = 990 J

You might be interested in
8. A hiker walks 2.3 km east and then 4.1 km north. What is her displacement?
Zolol [24]
Firstly , draw the path 2.3 to east and 4.1 to the north. you’ll get a right - angle triangle . the hypotenuse is the displacement.

to find the distance , use Pythagoras theorem.

let the displacement = c

c ^ 2 = 2.3 ^ 2 + 4.1 ^ 2

c = 4.7 km

then , you need to find the angle.

tan theta = 4.1 / 2.3

theta = 61 degree

i am sorry if my answer was wrong but i hope it helps you and you can understand it : )
8 0
3 years ago
What kind of circuit is the one shown below?
xeze [42]

Since here two bulbs are connected in a line without any branching between them

Also there is same current through out the circuit in both bulbs

So it is SERIES combination of the circuit

here in series

current remains same

V = V_1 + V_2 ......

so correct answer is

<u>B. Series</u>

8 0
3 years ago
A circular loop with 30 turns and area of 0.25 m2 rotates at 100 rad/s. The axis of rotation of the loop is perpendicular to the
zysi [14]

Answer:

e = 30 V

Explanation:

given,

N = 30 turns

Area = 0.25 m²

angular speed = ω = 100 rad/s

Magnetic field = 0.04 T

maximum induced emf in the loop = ?

e = N B A ω

e = 30 x 0.04 x 0.25 x 100

e = 30 V

hence, the maximum emf induced in the loop is equal to e = 30 V

5 0
3 years ago
Which of the following describes a CHEMICAL PROPERTY? *
elena-s [515]
The answer is c or b because a chemical property reacts with oxygen  and it can be boil at 00 degrees Celsius but it can float in water so the answer is b,c,d,e.
3 0
4 years ago
In an evaporation of water experiment, the initial mass of water in a beaker was 10.5775 +/- 0.0002 g. After some time, the mass
muminat

Answer:

Explanation:

The theory of  propagation of error in case of addition and subtraction states that maximum errors are added in absolute terms in both the operation of addition and subtraction . So in this case the subtracted value will be

10.5775 - 10.3005

= .2770 g

errors will be added ie in subtracted value we can find error to the tune of

.0002 + .0002 = .0004 g

So the subtracted value will be written as

.2770 ± .0004

7 0
3 years ago
Read 2 more answers
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