1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sav [38]
3 years ago
14

In a process for producing acetic acid, oxygen gas is bubbled into acetaldehyde, CH3CHO, containing manganese(II) acetate (catal

yst) under pressure at 60°C. 2CH3CHO(l) + O2(g) → 2HC2H3O2(l) In a laboratory test of this reaction, 22.2 g CH3CHO and 12.6 g O2 were put into a reaction vessel. We wish to predict the following: a) How many grams of acetic acid can be produced by this reaction from these amounts of reactants?
Chemistry
1 answer:
grigory [225]3 years ago
8 0

<u>Answer:</u> The mass of acetic acid that can be produced is 30.24 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For acetaldehyde:</u>

Given mass of acetaldehyde = 22.2 g

Molar mass of acetaldehyde = 44 g/mol

Putting values in equation 1, we get:

\text{Moles of acetaldehyde}=\frac{22.2g}{44g/mol}=0.504mol

  • <u>For oxygen gas:</u>

Given mass of oxygen  gas = 12.6 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{12.6g}{32g/mol}=0.394mol

The given chemical equation follows:

2CH_3CHO(l)+O_2(g)\rightarrow 2CH_3COOH(l)

By Stoichiometry of the reaction:

2 moles of acetaldehyde reacts with 1 mole of oxygen gas

So, 0.504 moles of acetaldehyde will react with = \frac{1}{2}\times 0.504=0.252mol of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent.

Thus, acetaldehyde is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of acetaldehyde produces 2 moles of acetic acid

So, 0.504 moles of acetaldehyde will produce = \frac{2}{2}\times 0.504=0.504moles of acetic acid

Now, calculating the mass of acetic acid from equation 1, we get:

Molar mass of acetic acid = 60 g/mol

Moles of acetic acid = 0.504 moles

Putting values in equation 1, we get:

0.504mol=\frac{\text{Mass of acetic acid}}{60g/mol}\\\\\text{Mass of acetic acid}=(0.504mol\times 60g/mol)=30.24g

Hence, the mass of acetic acid that can be produced is 30.24 grams

You might be interested in
Given the reaction:
Nadusha1986 [10]
Your answer will be B 
8 0
3 years ago
Read 2 more answers
Use your knowledge of valence electrons and how they affect bonds to figure out how carbon (Group 14) and oxygen (Group 16)
kenny6666 [7]

Answer: D

Explanation:

O=C=O

5 0
3 years ago
Which object will experience the strongest gravitational attraction to Earth?
Orlov [11]

Answer:

A

Explanation:

The strength of the gravitational force between two objects depends on mass and distance. The object with the greatest mass would be the car.

3 0
3 years ago
The flask contains 10.0 mL of HCl and a few drops of phenolphthalein indicator. The buret contains 0.160 M NaOH. It requires 18.
olchik [2.2K]

Answer:

Approximately 0.291\; \rm M (rounded to two significant figures.)

Explanation:

The unit of concentration \rm M is the same as \rm mol \cdot L^{-1} (moles per liter.) On the other hand, the volume of both the \rm NaOH solution and the original \rm HCl solution here are in milliliters. Convert these two volumes to liters:

  • V(\mathrm{NaOH}) = 18.2\; \rm mL = 18.2 \times 10^{-3}\; \rm L = 0.0182\; \rm L.
  • V(\text{$\mathrm{HCl}$, original}) = 10.0\; \rm mL = 10.0\times 10^{-3}\; \rm L = 0.0100\; \rm L.

Calculate the number of moles of \rm NaOH in that 0.0182\; \rm L of 0.160\; \rm M solution:

\begin{aligned} n(\mathrm{NaOH}) &= c(\mathrm{NaOH})\cdot V(\mathrm{NaOH})\\ &= 0.160\; \rm mol \cdot L^{-1} \times 0.0182\; \rm L \approx 0.00291\; \rm mol\end{aligned}.

\rm HCl reacts with \rm NaOH at a one-to-one ratio:

\rm HCl\; (aq) + NaOH\; (aq) \to NaCl\; (aq) + H_2O\; (l).

Coefficient ratio:

\displaystyle \frac{n(\mathrm{HCl})}{n(\mathrm{NaOH})} = 1.

In other words, one mole of \rm NaOH would neutralize exactly one mole of \rm HCl. In this titration, 0.291\; \rm mol of \rm NaOH\! was required. Therefore, the same amount of \rm HC should be present in the original solution:

\begin{aligned}&n(\text{$\mathrm{HCl}$, original})\\ &= n(\mathrm{NaOH})\cdot \frac{n(\mathrm{HCl})}{n(\mathrm{NaOH})} \\ &\approx 0.00291\; \rm mol \times 1 = 0.00291\; \rm mol\end{aligned}.

Calculate the concentration of the original \rm HCl solution:

\displaystyle c(\text{$\mathrm{HCl}$, original}) = \frac{n(\text{$\mathrm{HCl}$, original})}{V(\text{$\mathrm{HCl}$, original})} \approx \frac{0.00291\; \rm mol}{0.0100\; \rm L} \approx 0.291\; \rm M.

5 0
3 years ago
How many divisions are used to classify living organisms?<br> a) 5<br> b) 6<br> c) 8<br> d) 7
Nataly_w [17]
Answer:a

Living things are divided into five kingdoms: animal, plant, fungi, protist and monera
4 0
3 years ago
Other questions:
  • What is the concentration of your solution?
    14·1 answer
  • __________ force is the force of attraction and repulsion between subatomic particles.
    11·1 answer
  • Mark all of the things that describe the Solar System.
    5·1 answer
  • Calculate the percentage by mass of water in magnesium sulfate heptahydrate, MgSO4•7H2O
    8·2 answers
  • Ammonium fluoride is considered which of the following? Ammonium fluoride is considered which of the following? ionic compound a
    5·1 answer
  • a solution contains 2.1 moles of HCl and has a molarity of 6.00 M what volume of the solution occupy.
    9·1 answer
  • Theoretical yield and percentage yield of:
    14·1 answer
  • How much volume (in cm3) is gained by a person who gains 12.3 lb of pure fat?
    11·1 answer
  • How many liters of oxygen (at STP) are required to form 10.5 grams of hydrogen
    5·1 answer
  • A new computer chip contains 4.71×1022 Si atoms. Determine the mass (in grams) of the silicon present in the computer chip.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!