Answer:
a) 0.714g of bicarbonate of soda are required.
b) 0.221g of Al(OH)₃ are required
Explanation:
The reactions of HCl with bicarbonate of soda and aluminium hydroxide are:
HCl + NaHCO₃ → H₂O + NaCl + CO₂
3 HCl + Al(OH)₃ → 3H₂O + AlCl₃
The moles of HCl that we need neutralize are:
50mL = 0.050L * (0.17mol / L) = 0.0085 moles HCl
To solve these problem we need to find the moles of the antacid using the chemical reaction and its mass using its molar mass;
<em>a) </em><em>Moles NaHCO₃ = Moles HCl = 0.0085 moles </em>
The mass is -Molar mass NaHCO₃: -84g/mol-
0.0085 moles * (84g / mol) = 0.714g of bicarbonate of soda are required
b) 0.0085 moles HCl * (1mol Al(OH)₃ / 3mol HCl) = 2.83x10⁻³ moles Al(OH)₃
The mass is -Molar mass: 78g/mol-:
2.83x10⁻³ moles Al(OH)₃ * (78g/mol) =
<h3>0.221g of Al(OH)₃ are required</h3>
Answer:
The part labelled Y is the chloroplast and its main function is to produce food for the plant in the reactions of photosynthesis.
Explanation:
Plants are autotrophic organisms in that they are able to manufacture their own food. Plants are able to manufacture their own food due to the presence of the cell organelle known as the chloroplast. The plant chloroplast has its own DNA and can reproduce independently, from the rest of the cell. They can as well produce amino acids and lipids required for the chloroplast membrane.
Chloroplasts are green-colored membrane-bound organelles found within the plant cell. Their green color is due to the presence of the pigment, chlorophyll. Chlorophyll in the chloroplasts are responsible for absorbing light energy from sunlight and using this absorbed energy to make simple sugars (carbohydrates) from carbon (iv) oxide and water. This is the main function of the chloroplasts in plant cells.
Photosynthesis occurs in the chloroplasts in two reaction steps:
1. The light reaction - involves the splitting of e=water molecules using the energy of sunlight
2. The dark reactions - carbon (iv) oxide from the air is used to produce sugars.
1. Calcium & Nitrogen: Ca3N2
2. Aluminum & Chlorine: AlCl3
3. Aluminum & Nitrogen: AlN
4. Potassium & Bromine: KBr
5. Magnesium & Oxygen: MgO
6. Sodium & Sulfur: Na2S
Answer:
which one?
Explanation:
???????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
The question is as follows: What is the% m / m of a solution in which 22 g of solute are dissolved in 44 g of solvent?
Answer: The% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.
Explanation:
Given: Mass of solute = 22 g
Mass of solvent = 44 g
The percentage m/m is calculated using the following formula.
Substitute the values into above formula as follows.
Thus, we can conclude that the% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.
