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expeople1 [14]
3 years ago
11

How many moles of CO2 are produced when 5.00 moles of C2H5OH are burned? Please include the steps.

Chemistry
1 answer:
Burka [1]3 years ago
6 0
Just construct the chemical equation.Knowing that a molecule of ethanol has 2 carbon atoms, 2 molecules of carbon dioxide are produced.So the mol ratio of ethanol and CO2 is 1:2 ,so 10 mols of CO2 is produced.Of course this is under the assumption that it is burnt completely.If It is not burnt completely then thats a different story.
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1.30464 grams of glucose was present in 100.0 mL of final solution.

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Molarity=\frac{moles}{\text{Volume of solution(L)}}

Moles of glucose = \frac{18.5 g}{180 g/mol}=0.1028 mol

Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)

Molarity of the solution = \frac{0.1028 mol}{0.1 L}=1.028 mol/L

A 30.0 mL sample of above glucose solution was diluted to 0.500 L:

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Molarity of the solution after dilution = M_2

Volume of the solution after dilution= V_2=0.500L = 500 mL

M_1V_1=M_2V_2

M_2=\frac{M_1V_1}{V_2}=\frac{1.208 mol/L\times 30.0 mL}{500 mL}

M_2=0.07248 mol/L

Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:

Volume of solution = 100.0 mL = 0.1 L

0.07248 mol/L=\frac{\text{moles of glucose}}{0.1 L}

Moles of glucose = 0.07248 mol/L\times 0.1 L=0.007248 mol

Mass of 0.007248 moles of glucose :

0.007248 mol × 180 g/mol = 1.30464 grams

1.30464 grams of glucose was present in 100.0 mL of final solution.

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