Answer:
Oxidation states are used in chemistry solutions. It is a bond in which electron transfers easily from one nucleus to another nucleus.
Explanation:
- Oxidation-reduction reactions have some rules.
- The oxidation state is 0 at an uncombined bond.
- The bond of oxidation reduction is +1 in alkeli metal.
- The bond in two metal is +2
- The oxidation reduction state at helogens is -1. It does not happened always.
- The oxygen bond in oxidation and reduction is -2.
- The sum of the oxidation state is equal to the compound charges.
- In this process the changes occur for any elements. Redox could be occur. Its oxidized and reduction reaction can be seen in this process.
Whereas ionic bonds join metals to non-metals, metallic bonding joins a bulk of metal atoms. ... Sodium metal is therefore written as Na, not Na+. ... Both of these factors increase the strength of the bond still further. ... Heat capacity: This is explained by the ability of free electrons to move about the solid.
Answer:
London dispersion forces
Explanation:
There are different forces of attraction that helps to hold atoms or Molecules of a particular substance together. Some of the forces of attraction are ionic/ electrovalent bond, covalent bond, vander waals forces of attraction and so on.
Under the vander waals forces of attraction we have what is known as the London dispersion forces. This force of attraction is a very weak and it is commonly found in the atoms of noble gases.
The intermolecular force of attraction in which we are talking about that is london dispersion forces is formed as a result of the formation of non-polar dipoles which are not permanent.
Answer:
5446.8 J
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 50 g
Initial temperature (T₁) = 70 °C
Final temperature (T₂) = 192.4 °C
Specific heat capacity (C) = 0.89 J/gºC
Heat (Q) required =?
Next, we shall determine the change in the temperature. This can be obtained as follow:
Initial temperature (T₁) = 70 °C
Final temperature (T₂) = 192.4 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 192.4 – 70
ΔT = 122.4 °C
Finally, we shall determine the heat required to heat up the block of aluminum as follow:
Mass (M) = 50 g
Specific heat capacity (C) = 0.89 J/gºC
Change in temperature (ΔT) = 122.4 °C
Heat (Q) required =?
Q = MCΔT
Q = 50 × 0.89 × 122.4
Q = 5446.8 J
Thus, the heat required to heat up the block of aluminum is 5446.8 J
Organic chemical compounds as recommended by the (IUPAC)
