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2 years ago

The overall equation for the electrolysis of aluminium oxide is:

Chemistry

1 answer:

Alex Ar [27]2 years ago

6 0

941539.2 g of mass of oxygen is produced when 2000 kg of aluminium oxide is completely electrolysed.

<h3>What is electrolysis?</h3>

Electrolysis is the process by which electric current is passed through a substance to effect a chemical change.

The mass of aluminium oxide Al₂O₃ = 2000 kg = 2000 000 g

Molar mass of Al₂O₃ = 101.96 g/mol

no of moles = $\frac{mass }{ molar \;mass}$

no of moles of Al₂O₃ = $\frac{2000 000 g}{101.96 g/mol}$

no of moles of Al₂O₃ = 19615.4 mol

From the reaction:

4Al + 3O₂ ⇒ Al₂O₃

To determine the moles of O₂ in Al₂O₃:

Then;

19615.4 mol X $\frac{3}{2}$ mol of O₂ = 29423.1

The mass of oxygen now = 29423.1 × 32 g

= 941539.2 g

Hence, 941539.2 g of mass of oxygen is produced when 2000 kg of aluminium oxide is completely electrolysed.

Learn more about electrolysis here:

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Camphor, a white solid with a pleasant odor, is extracted from the roots, branches, and trunk of the camphor tree. Assume you di

katrin [286]

Answer: The molarity of solution is 0.799 M , molality of solution is 1.02 m, mole fraction of camphor is 0.045 and mass percent of camphor in solution is 13.43 %

Explanation:

Calculating the molarity of solution:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of camphor = 70.0 g

Molar mass of camphor = 152.2 g/mol

Volume of solution = 575 mL

Putting values in above equation, we get:

$\text{Molarity of camphor}=\frac{70\times 1000}{152.2\times 575}\\\\\text{Molarity of camphor}=0.799M$

Calculating the molarity of solution:

To calculate the mass of ethanol, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of ethanol = 0.785 g/mL

Volume of ethanol = 575 mL

Putting values in above equation, we get:

$0.785g/mL=\frac{\text{Mass of ethanol}}{575mL}\\\\\text{Mass of ethanol}=(0.785g/mL\times 575mL)=451.38g$

To calculate the molality of solution, we use the equation:

$\text{Molality of solution}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

$m_{solute}$ = Given mass of solute (camphor) = 70 g

$M_{solute}$ = Molar mass of solute (camphor) = 152.2 g/mol

$W_{solvent}$ = Mass of solvent (ethanol) = 451.38 g

Putting values in above equation, we get:

$\text{Molality of camphor}=\frac{70\times 1000}{152.2\times 451.38}\\\\\text{Molality of camphor}=1.02m$

Calculating the mole fraction of camphor:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For camphor:

Given mass of camphor = 70 g

Molar mass of camphor = 152.2 g/mol

Putting values in equation 1, we get:

$\text{Moles of camphor}=\frac{70g}{152.2g/mol}=0.459mol$

For ethanol:

Given mass of ethanol = 451.38 g

Molar mass of ethanol = 46 g/mol

Putting values in equation 1, we get:

$\text{Moles of ethanol}=\frac{451.38g}{46g/mol}=9.813mol$

Mole fraction of a substance is given by:

$\chi_A=\frac{n_A}{n_A+n_B}$

Moles of camphor = 0.459 moles

Total moles = [0.459 + 9.813] = 10.272 moles

Putting values in above equation, we get:

$\chi_{(camphor)}=\frac{0.459}{10.272}=0.045$ \

Calculating the mass percent of camphor:

To calculate the mass percentage of camphor in solution, we use the equation:

$\text{Mass percent of camphor}=\frac{\text{Mass of camphor}}{\text{Mass of solution}}\times 100$

Mass of camphor = 70 g

Mass of solution = [70 + 451.38] = 521.38 g

Putting values in above equation, we get:

$\text{Mass percent of camphor}=\frac{70g}{521.38g}\times 100=13.43\%$

Hence, the molarity of solution is 0.799 M , molality of solution is 1.02 m, mole fraction of camphor is 0.045 and mass percent of camphor in solution is 13.43 %

3 0

3 years ago

Which phrase describes a hypothesis? a. reviewing information related to the problem b. testing a factor, or variable, in an exp

monitta

Answer:

c. suggesting a solution to a problem after studying it carefully

Explanation:

Hypothesis generally refers to an assumption made. This assumption can either be true or false. It is a reasoning presented in order to explain a phenomenon and is the starting point for further investigation.

Among the options, the closest that best describes it is option C.

4 0

3 years ago

How much heat is lost or gained by the calorimeter

Maslowich

Answer:

1.113 kJ or 1,113 J.

Explanation:

I hope this helps :)

5 0

3 years ago

What’s the fastest way to balance chemical equations

Anon25 [30]

Hey there!

The best way to balance chemical equations is to first start by balancing polyatomic ions such as OH and SO₄.

Next, balance other elements, but save elements that are by themselves for last, such as H₂ or Fe. Once you balance everything else you can do the ones by themselves, it's much easier.

Hope this helps!

6 0

3 years ago

a block of iron has the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. it has a mass of 213 g. what is its density? a. 638 g/cm3 b.

Juliette [100K]

Volume = 3 cm × 3cm × 3cm
= 27 cm ³

Mass = 213 g

Density = $\frac{MASS}{VOLUME}$

= $\frac{213 g}{27 cm ^{3} }$

 = 7.89 g / cm³

Thus answer is D.

8 0

3 years ago

Read 2 more answers