1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dafna11 [192]
3 years ago
5

The Element rhenium has two naturally occurring isotopes, 185 Re and 187 Re, with an average atomic mass of 186.207 amu. Rhenium

is 62.60% 187 Re, and the atomic mass of 187 Re is 186.956 amu. Calculate the mass of 185 Re. How do you do this?
Chemistry
1 answer:
BigorU [14]3 years ago
8 0
To calculate the average mass of the element, we take the summation of the product of the isotope and the percent abundance. In this case, the equation becomes 186.207=187*0.626+185*x where x is the percent abundance of 185. The answer is 0.374 or 37.4%. This can also be obtained by 100%-62.6%= 37.4%. 
You might be interested in
Mercury may have lost part of its mantle and crust to a _______ leaving it with a large, metal _______.
igomit [66]
<h2>Giant impact and metalcore.</h2>

Explanation :

  • Mercury has a large core of liquid metal.
  • The metal core is of iron metal.
  • The core is surrounded by a mantle which is made up of silica and a solid outer crust.
  • In the case of Mercury, the total core percentage is 42% of the planet while the Earth's core is only 17% of the planet.
  • Mercury has lost part of its mantle and crust that left the mercury with a large metal core.

3 0
3 years ago
What comes in contact with Sodium Hydroxide to form soap and glycerine it is a chemical change because you cannot reverse this c
svetoff [14.1K]

Answer:

Your answer is triglycerides. Hope this helps.

8 0
3 years ago
Ricardo compra un gaseosa en el súper al destaparla la gaseosa comienza a salir espuma y vuelca la mitad al piso ¿Por qué puede
dimaraw [331]

Answer:

Las bebidas gaseosas como las gaseosas están hechas de un soluto de dióxido de carbono gaseoso en un líquido. La solubilidad del dióxido de carbono en el líquido depende de la presión y la temperatura de la lata de refresco, y también de agitar la lata de refresco que introduce burbujas que permanecen ocultas hasta que se abre la lata antes de que burbujee.

Por lo tanto, dado que la presión en la lata de refresco permanece constante, elevar la temperatura, agitar la lata de refresco o congelar el refresco, lo que aumenta la cantidad de dióxido de carbono en la porción líquida, hará que el refresco forme espuma y se derrame.

Explanation:

8 0
3 years ago
Colloids and suspension are described as ________ heterogeneous _________ mixtures
solong [7]

The question is already answered.

3 0
3 years ago
What term is used for the chemical composition of a compound​
postnew [5]

Relative molecular mass or RMM is the answer.

4 0
3 years ago
Other questions:
  • In order to derive a simplified version of the Nernst equation by assuming standard temperature we can substitute which of the f
    8·1 answer
  • How many protons, electrons, and neutrons does an atom with atomic number 50 and mass number 125 contain?
    12·1 answer
  • An atom has atomic number 5 and mass number 11. How many protons does the atom have? 5 6 10 11
    6·2 answers
  • What is the density of an object with a mass of 40.0 g and a volume of 80.0 cm3
    14·1 answer
  • Which best describes thermal energy?
    8·1 answer
  • if the temperature increases and the barometric pressure Falls then which symbols will denote this on a weather map
    10·2 answers
  • a solution must be at a higher temperature than a pure solvent to boil. what colligative property can be employed to achieve thi
    8·2 answers
  • Electromagnetic energy that travels in transverse waves which produces visible light is
    9·1 answer
  • Calculate molar concentration of formic acid solution if degree of dissociation is 4% K(HCOOH)=2.10^_4
    6·1 answer
  • What is the mass of 1 atom?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!