Answer:
1. 22 moles of FeCr2O7
2. 53.95 moles of O2
3. 77.25 moles of O2
Explanation:
4 FeCr2O7+ 8 K2CO3 + 1 O2-----------> 2 Fe2O3+ 8 K2CrO4 + 8 CO2
1. How many moles of FeCr2O7 are required to produce 44 moles of CO2?
Equate the moles of the compounds in the question
4 moles of FeCr2O7 produces 8 moles of CO2
(44 *4 / 8) moles of FeCr2O7 will produce 44 moles of CO2
= 44 *4 / 8
= 22 moles
2. How many moles of 02 is required to produce 107.9 moles of Fe2O3?
1 mole of O2 = 2 moles of Fe2O3
(107.9 *1 / 2) moles of O2 will be required to produce 107.9 moles of Fe2O3
= 107.9 * 1 / 2
= 53.95 moles
3. The ratio of moles for FeCr2O7 to O2 in the reaction is
4 : 1
309 : x ; solve for x
x = 309 * 1 / 4
x =77.25 moles of O2
Answer: as copper has lower electrode potential value than hydrogen, it could be reduced by hydrogen.
Explanation: hydrogen has zero reduction potential while Cu has +0.34V and Al has -1.66 V .
SO in electrochemical series who has most negative or less reduction potential value tends to be a good reducing agent than the other.
Hope it helps...
It would 3 because if you read it tells you the answer
Answer:
False
Explanation:
The urine is produced in the kidneys, each one of the kidneys is connected to a ureter. The ureter is a tube that propels the excreted urine to the urinary bladder. The urinary bladder is a deposit for the urine, here is collected and stored before disposal. After the urinary bladder, the urine goes through the urethra, which is a tube, to exit the body.
