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Svetlanka [38]
3 years ago
8

The diagram below shows some waves traveling along a rope.

Physics
1 answer:
Harrizon [31]3 years ago
3 0

-- Well first of all, the waves are <em>transverse waves</em>.  The fibers in the rope, and the hand that generates the waves, are moving up and down, but the wave is moving to the right, towards the wall.  These directions are perpendicular.

-- Later on, after the waves reflect from the wall and travel back toward the hand, there are going to be <em>standing waves</em> on the rope.  But this is probably beyond the scope of the question.

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A box of mass 14 kg sits on an inclined surface with an angle of 52degrees. What is the component of the weight of the box along
kolezko [41]
First, we calculate for the weight of the object by multiplying the given mass by the acceleration due to gravity which is equal to 9.8 m/s²
                       Weight = (14 kg)(9.8 m/s²)
                          Weight = 137.2 N
The component of the weight that is along the surface of the inclined plane is equal to this weight times the sine of the given angle. 
                         Weight = (137.2 N)(sin 52°)
                               weight = 108.1 N
5 0
3 years ago
Read 2 more answers
A ramp is 1.0 m high and 3.0 m long. What is the IMA of the ramp?
oksano4ka [1.4K]
To calculate the ideal mechanical advantage for an inclined plane, divide th length of the incline by the height of the incline. 
Therefore; IMA = L/h
L= 3.0 m, while h =1.0 m
 IMA = 3/1
         = 3
Therefore the IMA of the ramp is 3 
This means the ramp increases the force that is being exerted by 3 times.
4 0
3 years ago
A 1200 kg sports car accelerates from 0 m/s to 30 m/s in 10 s. What is the average power of the engine?
DIA [1.3K]

Answer:

3600N

Explanation:

Given: m = 1200kg, Vo = 0m/s, Vf = 30m/s, Δt = 10s

ΣF = ma

we need to find 'a' first, using the definition of 'a' we get equation:

a = (Vf-Vo)/Δt

a = (30m/s)/10s

a = 3 m/s^2

now substitute into top equation

ΣF = ma

Fengine = (1200kg)(3m/s^2)

Fengine = 3600N

5 0
2 years ago
Read 2 more answers
1. A soccer ball is kicked horizontally off a cliff with an initial speed of 8 m/s and lands 16 m from the base of
lana66690 [7]

Answer:

Height of cliff = S = 20 m (Approx)

Explanation:

Given:

Initial velocity = 8 m/s

Distance s = 16 m

Starting acceleration (a) = 0

Computation:

s = ut + 1/2a(t)²

16 = 8t

t = 2 sec

Height of cliff = S

Gravitational acceleration = 10 m/s

S = 1/2a(t)²

S = 1/2(10)(2)²

Height of cliff = S = 20 m (Approx)

3 0
3 years ago
The gage pressure in a liquid at a depth of 3 m is read to be 39 kPa. Determine the gage pressure in the same liquid at a depth
ioda

Answer: 117 kPa

Explanation:

For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa

For the liquid at depth 9m, the gauge pressure is equal to= P₂

Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.

So, For finding gauge pressure we have formula P= ρ * g * h

Also gravity also remains same for both liquids

So taking ratio of their respective pressures we have

\frac{P_{1} }{\\P_2}= \frac{density * g * h_1}{density * g * h_2}

So \frac{39}{P_2}= \frac{3}{9}

Or P₂= 39 * 3 = 117 kPa

5 0
3 years ago
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