F = ma
We have mass = 0.2kg
and acceleration = 20 m/s^2
So..
F = (0.2)(20)
F = 4 N
Answer:
(i) Electric field outside the shell:
For point r>R; draw a spherical gaussian surface of radius r.
Using gauss law, ∮E.ds=q0qend
Since E is perpendicular to gaussian surface, angle betwee E is 0.
Also E being constant, can be taken out of integral.
So, E(4πr2)=q0q
So, E=4πε01r2q
Ahhh, there aren’t option to work with :v
Try writing them down here thnx
Answer:
Distance is 500 m, displacement is 0
Explanation:
Distance and displacement are defined in two different ways:
- Distance is the total length of the path covered by an object in motion - so it depends on the path taken. In this problem, the distance travelled by the car corresponds to the length of one lap, which is the length of the track, so 500 m
- Displacement is the distance in a straight line between the final point and the initial point of the motion. This means that displacement does not depend on the path taken, but only on the starting and ending point of the motion. In this problem, the car completes one lap, so the final position of the car is equal to its starting position - therefore the displacement is zero, since the distance between these two points is zero.
Answer:
0.26
Explanation:
Given that :
Diameter of ball = 3.81 cm = 3.81/100 = 0.0381 m
Radius (r) = 0.0381 / 2 = 0.01905 m
Average density of ball (Db) = 0.0842 g/cm³ = (0.0842 / 1000)kg / 10^-6 = 0.0842/ 1000 * 10^6 = 84.2kg/m³
Density of water (Dw) = 1000kg/m³
Volume of hollow ball: (4/3) * pi * r³
V = (4/3) * π * 0.01905^3
V = 0.0000289583 m³
Required force = (Dw * V * g) - (Db * V * g)
= (1000 * 0.0000289583 * 9.8) - (84.2 * 0.0000289583 * 9.8)
= 0.259896109172
= 0.2598 N
