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Anni [7]
4 years ago
14

Hi, Please help me with these definitions:

Chemistry
2 answers:
Vladimir79 [104]4 years ago
5 0

Answer:

Ecosystem

Explanation:

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irakobra [83]4 years ago
4 0

Answer:

The answer is actually Thermal Pollution

Explanation:

I just finished my USATestprep for this.

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How many milligrams of sugar are in a teaspoon of sugar
grigory [225]

Answer 2325 milligrams.

Explanation:The unit is abbreviated as tsp. Convert Milligrams (mg) to Teaspoons (tsp): 1 mg is approximately equal to 0.0002 tsps. One milligram is a relatively small quantity of table sugar A mere one-teaspoon of granulated sugar contains some 2325 milligrams. Yay wiki

6 0
3 years ago
An electron in an atom is known to be in a state with magnetic quantum number ml=−1
Ulleksa [173]

Explanation:

It is known that the maximum value of ml is equal to the vale of l. But the minimum value of n is as follows.

                    n = l + 1

where,     n = principle quantum number

                l = azimuthal quantum number

Values of n can be 1, 2, 3, 4 and so on. Whereas the values of l can be 0, 1, 2, 3, and so on.

Also, "m" is known as magnetic quantum number whose values can be equal to -l and +l.

So, when n = 1 then l = 0 and m = 0.

When n = 2 then l = 1 and values of m will be equal to -1, 0, +1. As it is given that the magnetic quantum number ml = -1. Hence, it is only possible when n = 2.

Thus, we can conclude that the smallest possible value of the principal quantum number n of the state is 2.

5 0
3 years ago
Palladium (Pd; Z 46) is diamagnetic. Draw partial orbital diagrams to show which of the following electron configurations is con
nexus9112 [7]

Answer : The electron configurations consistent with this fact is, (b) [Kr] 4d¹⁰  

Explanation :

Electronic configuration : It is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom are determined by the electronic configuration.

Paramagnetic compounds : They have unpaired electrons.

Diamagnetic compounds : They have no unpaired electrons that means all are paired.

The given electron configurations of Palladium are:

(a) [Kr] 5s²4d⁸

In this, there are 2 electrons in 's' orbital and 8 electrons in 'd' orbital. From the partial orbital diagrams we conclude that 's' orbital are paired but 'd' orbital are not paired. So, this configuration shows paramagnetic.

(b) [Kr] 4d¹⁰

In this, there are 10 electrons in 'd' orbital. From the partial orbital diagrams we conclude that electrons in 'd' orbital are paired. So, this configuration shows diamagnetic.

(c) [Kr] 5s¹4d⁹

In this, there are 1 electron in 's' orbital and 9 electrons in 'd' orbital. From the partial orbital diagrams we conclude that 's' orbital and 'd' orbital are not paired. So, this configuration shows paramagnetic.

6 0
4 years ago
Which of the following molecules has only single bonds?
mel-nik [20]

Answer:

C

Explanation:

it only bonded with one other molecule carbon/ oxgen=carbon dioxide

6 0
4 years ago
When 400 J of heat are slowly added to 10 mol of an ideal monatomic gas, its temperature rises by 10°C. What is the work done on
Molodets [167]

When 400 J of heat are slowly added to 10 mol of an ideal monatomic gas, its temperature rises by 10°C. The work done on the gas is 845J.

The amount of work done on gas depends upon the internal energy change and the heat supplied to the system.

According to First Law of Thermodynamics, the change in internal energy is equal to the work done and the heat supplied to the system.

This is given by:

ΔU = W + Q

where, ΔU is change in Internal energy

            W is the Work done

            Q is the heat supplied

Given,

Q = 400J

Number of moles, n = 10

Change in temperature, ΔT = 10°C

Cv = 3/2R ; Since, the given gas is monoatomic (R=8.3)

We know that, ΔU = n Cv ΔT

On substituting the values in above formula,

ΔU = 10 × 3/2 × 8.3 × 10

ΔU = 1245J

Using,

ΔU = W + Q

1245J = W + 400

W = 845J

Hence, the work done on the gas is 845J.

Learn more about Thermodynamics here, brainly.com/question/1368306

#SPJ4

7 0
2 years ago
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