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REY [17]
3 years ago
11

Find the perimeter of the square and then convert the answer to meters

Chemistry
1 answer:
insens350 [35]3 years ago
8 0
The answer should be 2.4 meters.

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A different student is given a 10.0g sample labeled CaBr2 that may contain an inert (nonreacting) impurity. Identify a quantity
grandymaker [24]

Answer:

Mass of Ca in sample, Mass of Br in sample, Number of moles of Ca in sample, Number of moles of Br in sample, Mass or moles of element other than Ca or Br in sample

Explanation:

The AP Classroom will not count your answer to this question as correct unless it includes at least one of the answers listed above. If you say that theanswer to this question is density, it will be marked as incorrect, I found that out the hard way when I used the answers that brainly gave me.

Good luck,

I applaud you for using the sources avalible to you, which is /definetly not/ cheeting.

8 0
2 years ago
What are the number of protons, electrons, and neutrons in Potassium
gayaneshka [121]
<span><span>Number of Protons-19 </span><span>Number of Neutrons-20 </span><span>Number of Electrons-<span>19</span></span></span>
4 0
3 years ago
Read 2 more answers
Which of the following is an example of how a scientist might use a model?
anzhelika [568]

D Microscopes

because they use them for DNA

a,b,and c, all you an item that can be used and not tested with.

4 0
3 years ago
Read 2 more answers
What kind of air is found in each high and low pressure area
dolphi86 [110]
Hydrogen and oxygen and nitrogen.
3 0
3 years ago
A reaction is followed and found to have a rate constant of 3.36 × 104 m-1s-1 at 344 k and a rate constant of 7.69 m-1s-1 at 219
g100num [7]

The relation between rate constants at different temperatures, temperature and activation energy is known as Arrhenius equation

<u>Arrhenius equation</u>

K=Ae^-{\frac{Ea}{RT} }

For two temperatures

Ea=R(\frac{ln\frac{k1}{k1} }{(\frac{1}{T1})-(\frac{1}{T2})})

Where

Ea = ? = activation energy

k1 = 3.36 × 10⁴

T1=344 k

k2=7.69

T2=219K

R= gas constant = 8.314 J /molK

Putting values

Ea= (8.314)(\frac{ln(\frac{7.69}{33600})}{(\frac{1}{344})(\frac{1}{219})}

Ea = (-69.69)/(-0.00166) = 41981.93 J/mol

Or

Activation energy is 42.0 kJ /mol

3 0
2 years ago
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