How high is the rocket when the canister hits the launch pad, assuming that the rocket does not change its acceleration?

Physics

1 answer:

aalyn [17]3 years ago

7 0

There is too much information given, it's hard to understand exactly which variables are important in this problem.

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Most restaurants serve suggested serving sizes for one person.

sweet-ann [11.9K]

I'm not really sure what you are asking. I will try though. The main serving sizes as you know are:
1.Small
2.Medium
3.Large
To me, it depends on the person that is ordering the food, and what size they want it to come in. I hope that helped.

7 0

4 years ago

Read 2 more answers

A majorette in a parade is performing some acrobatic twirlings of her baton. Assume that the baton is a uniform rod of mass 0.12

den301095 [7]

Question

Initially, the baton is spinning about a line through its center at angular velocity 3.00 rad/s. What is its angular momentum? Express your answer in kilogram meters squared per second.

Answer:

$0.0192 kgm^{2}/s$

Explanation:

The angular momentum L of the baton moving about an axis perpendicular to it, passing through the center of the baton is,

$L = \frac{1}{{12}}m{l^2}\omega$

Here, l is the length of the baton.

Substitute 0.120 kg for m, 3 rads/s for $\omega[\tex] and 0.8 m for l [tex]\begin{array}{c}\\L = \frac{1}{{12}}m{l^2}\omega \\\\ = \frac{1}{{12}}\left( {0.120{\rm{ kg}}} \right){\left( {{\rm{80}}{\rm{.0 cm}}} \right)^2}{\left( {\frac{{1 \times {{10}^{ - 2}}{\rm{m}}}}{{1{\rm{ cm}}}}} \right)^2}\left( {{\rm{3}}{\rm{.00 rad/s}}} \right)\\\\ = 0.0192{\rm{ kg}} \cdot {{\rm{m}}^{\rm{2}}}{\rm{/s}}\\\end{array}$