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user100 [1]
2 years ago
15

How high is the rocket when the canister hits the launch pad, assuming that the rocket does not change its acceleration?

Physics
1 answer:
aalyn [17]2 years ago
7 0
There is too much information given, it's hard to understand exactly which variables are important in this problem. 
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Jail
kykrilka [37]

Answer:

c.o Kg • ms 08

Explanation:

put all together

7 0
3 years ago
A persons height will be the same on jupiter and earth. A persons weight will be greater on jupiter than on earth. True or false
Feliz [49]
That is true. its more than twice as heavier
5 0
3 years ago
Deep in the interiors of the giant planets, water is still a liquid even though the temperatures are tens of thousands of degree
Nataliya [291]

Answer:

High pressure inside the giant planet

Explanation:

As we move in the interior of the giant planet, the pressure and temperature in the interior of the planet increases. Since, the giant planets have hardly any solid surface and thus they are mostly constituted of atmosphere.

Also, the gravitational forces keep even the lightest of the matter bound in it contributing to the large mass of the planet.

If we look at the order of the magnitude of the temperature of these giant planets than nothing should be able to stay in liquid form but as the depth of the planet increases with the increase in temperature, pressure also increases which keeps the particle of the matter in compressed form.

Thus even at such high order of magnitude water is still found in liquid state in the interior of the planet.

7 0
3 years ago
Approximately how many kelvins are equal to 60°c?
ella [17]

333.15 Kelvins are equal to 60 degrees celsius

8 0
3 years ago
Read 2 more answers
Assuming there are no accidents or delays, the distance that a car travels down the interstate
Ganezh [65]

Explanation:

The distance that a car travels down the interstate  can be calculated with the following formula:

Distance = Speed x Time

(A) Speed of the car, v = 70 miles per hour = 31.29 m/s

Time, d = 6 hours = 21600 s

Distance = Speed x Time

D = 31.29 m/s × 21600 s

D = 675864 meters

or

D=6.75\times 10^5\ m

(b) Time, d = 10 hours = 36000 s

Distance = Speed x Time

D = 31.29 m/s × 36000 s

D = 1126440 meters

or

D=1.12\times 10^6\ m

(c) Time, d = 15 hours = 54000 s

Distance = Speed x Time

D = 31.29 m/s × 54000 s

D = 1689660 meters

or

D=1.68\times 10^6\ m

Hence, this is the required solution.

7 0
2 years ago
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