A tire placed on a balancing machine in a service station starts from rest and turns through 4.0 rev in 1.0 s before reaching it
2 answers:
Answer:
a = 50.26 rad/s^2
Explanation:
We know that:
θ =
where θ is the angle, a the angular aceleration and t the time.
First, we need to find how many rad are equivalent to 4 rev, as:
θ = 4 rev * 2π = 25.13 rad
Finally, replacing θ by 25.13 rad and t by 1 second, we get:
25.13 rad =
Solving for a:
a = 50.26 rad/s^2
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Answer:
a) The distance of spectator A to the player is 79.2 m
b) The distance of spectator B to the player is 43.9 m
c) The distance between the two spectators is 90.6 m
Explanation:
a) Knowing the time it takes the sound to reach both spectators, we can calculate their position relative to the player, using this equation:
x = v * t
where:
x = position of the spectators
v = speed of sound
t = time
Then, the position for spectator A relative to the player is:
x = 343 m/s * 0.231 s = 79.2 m
b)For spectator B:
x = 343 m/s * 0.128 s
x = 43.9 m
The distance of spectator A and B to the player is 79.2 m and 43.9 m respectively.
c) To calculate the distance between the spectators, please see the attached figure. Notice that the distance between the spectators is the hypotenuse of the triangle formed by the sightline of both. We already know the longitude of the two sides. Then, using Pythagoras theorem:
(Distance AB)² = A² + B²
(Distance AB)² = (79.2 m)² + (43.9 m)²
Distance AB = 90. 6 m
Answer:
1.2 * 10' -8N (Check attachment
Explanation:
Check attachment
