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4 years ago

If the earth can travel 1800 km in 1 minute what is it’s speed in km/s

Physics

1 answer:

Lady bird [3.3K]4 years ago

4 0

Answer:

30km/s

Explanation:

1800/60=30

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Calculate the magnitude of the force between two point charges where q1 = +5.30 ?C and Q2 = +11.2 11C where the separation betwe

MA_775_DIABLO [31]

Answer:

Magnitude of force, F = 11 Newtons

Explanation:

Charge 1, $q_1=5.3\ \mu C=5.3\times 10^{-6}\ C$

Charge 2, $q_2=11.2\ \mu C=11.2\times 10^{-6}\ C$

The separation between the charges is, r = 0.22 m

We have to find the magnitude of the force between two point charges. It can be calculated using the formula as :

$F=k\dfrac{q_1q_2}{r^2}$

$F=9\times 10^9\times \dfrac{5.3\times 10^{-6}\ C\times 11.2\times 10^{-6}\ C}{(0.22\ m)^2}$

F = 11.03 N

F = 11 Newtons

Hence, this is the required solution.

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3 years ago

A particle is projected from a point on a horizontal plane and has an initial velocity of 28root 3 m/s at an angle of 60 degree

Lelechka [254]

Answer:

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3 years ago

What type of circuit is illustrated

Varvara68 [4.7K]

The bulbs are in parallel.

The picture doesn't show enough of the circuit to tell
whether it's also open or shorted. It may be either, or
it may be neither.

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3 years ago

A 5.0-Ω resistor and a 9.0-Ω resistor are connected in parallel. A 4.0-Ω resistor is then connected in series with this parallel

Oliga [24]

Answer:

Explanation:

The current through the resistor is 0.83 A

Part b

The current through resistor is 0.53 A

Part c

The current through resistor is 0.30 A

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3 years ago

A 105 kg football player runs at 8.5 m/s and plows into the back of an 85 kg referee running at 3.5 m/s on the field causing the

Vedmedyk [2.9K]

Answer:

680 Kg.m/s

Explanation:

Mass of player; m_p = 105 kg.

Speed of player before Collision; v_pi = 8.5 m/s

Mass of referee; m_r = 85 kg

Speed of referee before collision; v_ri = 3.5 m/s

Speed of referee after collision; v_rf = 6 m/s

From conservation of momentum,

Initial momentum = final momentum

Thus;

(m_p × v_pi) + (m_r × v_ri) = (m_p × v_pf) + (m_r × v_rf)

Where (m_p × v_pf) is the momentum of the player after collision.

Thus, Plugging in the relevant values, we have;

(105 × 8.5) + (85 × 3.5) = (m_p × v_pf) + (85 × 6)

(m_p × v_pf) = (105 × 8.5) + (85 × 3.5) - (85 × 6)

(m_p × v_pf) = 680 Kg.m/s

3 0

3 years ago