Answer:
a)
a = 1/5
b = 1/3
b)
x(1/3) = 2.500
y(1/3) = 2.598
c)
x'(t) = -5π sin(π t)
d)
x'(1/3) = -13.603
Explanation:
Hi!
a)
We can notice that
x(t)/5 = cos(πt)
y(t)/3 = sin(πt)
Therefore:
( x(t) / 5 )^2 + ( y(t) / 3 )^2 = cos^2(πt) + sin^2(πt) = 1
That is:
a = 1/5
b = 1/3
b)
At t=1/3
x(1/3) = 5 cos(π/3)
y(1/3) = 3 sin(π/3)
But
cos(π/3) = 1/2 = 0.5
sin(π/3) = √3 / 2 = 0.866
That is:
x(1/3) = 2.5
y(1/3) = 2.598
c)
The horizontal velocity is:
x'(t) = -5π sin(π t)
d)
at time t =1/3
x'(1/3) = -5π sin(π/3) = -13.603
Answer:
Height is 11.25m
Explanation:
<u>Given the following data;</u>
Initial velocity, u = 0
Final velocity, v = 15m/s
Acceleration due to gravity, g = 10m/s²
To find the height, we would use the third equation of motion;
Where;
- V represents the final velocity measured in meter per seconds.
- U represents the initial velocity measured in meter per seconds.
- a represents acceleration measured in meters per seconds square.
- S represents the displacement (height) measured in meters.
<em>Making S the subject, we have;</em>

But a = g = 10m/s²
<em>Substituting into the equation, we have;</em>

S = 11.25m
<em>Therefore, the ball will reach a height of 11.25m before it begins to fall. </em>
Answer:
The mass of moon is 1/100 times and its radius 1/4 times that of earth. As a result, the gravitational attraction on the moon is about one sixth when compared to earth. Hence, the weight of an object on the moon is 1/6th its weight on the earth.
Answer:
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