Answer:
The wavelength is 3500 nm.
Explanation:
d=
n= 1
θ= 30°
λ= unknown
Solution:
d sinθ = nλ
λ =
λ = 3500 nm
Any value giving up from the best alternative is called
1 answer:
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Answer:
Maximum height attained by the model rocket is 2172.87 m
Explanation:
Given,
- Initial speed of the model rocket = u = 0
- acceleration of the model rocket =
- time during the acceleration = t = 2.30 s
We have to consider the whole motion into two parts
In first part the rocket is moving with an acceleration of a = 85.0 for the time t = 2.30 s before the fuel abruptly runs out.
Let be the height attained by the rocket during this time intervel,
And Final velocity at that point be v
Now, in second part, after reaching the altitude of 224.825 m the fuel abruptly runs out. Therefore rocket is moving upward under the effect of gravitational acceleration,
Let '' be the altitude attained by the rocket to reach at the maximum point after the rocket's fuel runs out,
At that insitant,
- initial velocity of the rocket = v = 195.5 m/s.
- a =
- Final velocity of the rocket at the maximum altitude =
From the kinematics,
Hence the maximum altitude attained by the rocket from the ground is
Answer:
Explanation:
Average velocity = Displacement/Time
ΔS = -10+6
ΔS = -4m
Given tme = 30s
Average velocity = -4/30
Average velocity = -0.13m/s
Average speed = Distance/Time
Total distance covered = 10m+6m
Total distance covered = 16m
Average speed = 16/30
Average speed = 0.53m/s
