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s2008m [1.1K]
4 years ago
14

What do nuclear power plants use as a fuel source? Where is this fuel source obtained?

Chemistry
2 answers:
Sergeu [11.5K]4 years ago
8 0

Only 0.7% of natural uranium is 'fissile', or capable of undergoing fission, the process by which energy is produced in a nuclear reactor. The form, or isotope, of uranium which is fissile is the uranium-235 (U-235) isotope. ... Most is then converted into uranium hexafluoride, ready for the enrichment plant.

Dovator [93]4 years ago
5 0

Answer:

Use of fissionable elements to produce heat and is obtained in underground mines.

Explanation:

Nuclear plants use chemical elements that when subjected to nuclear reactions (fission or fusion) release considerable amounts of energy (heat). This heat is used to produce steam and move turbines that generate electrical energy.

The nuclear compounds are obtained mainly in underground mines, after this the compounds are extracted and subjected to purification processes the purified element is taken to nuclear power plants where they are used to obtain the electrical energy.

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A sample of hydrated magnesium sulfate (MgSO4)
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Explanation:

Let the formula for the hydrated magnesium sulphate be MgSO4.xH2O

Mass of the hydrated salt (MgSO4.xH2O) = 12.845g

Mass of anhydrous salt (MgSO4) = 6.273g

Mass of water molecule(xH2O) = Mass of the hydrated salt — Mass of anhydrous salt = 12.845 — 6.273 = 6.572g

Now,we can obtain the number of mole of water molecule present in the hydrated salt as follows:

Molar Mass of hydrated salt (MgSO4.xH2O) = 24 + 32 + (16x4) + x(2 + 16) = 24 + 32 + 64 + x(18) = 120 + 18x

Mass of xH2O/ Molar Mass of MgSO4.xH2O = Mass of water / mass of hydrated salt

18x/120 + 18x = 6.572/12.845

Cross multiply to express in linear form

18x x 12.845 = 6.572(120 + 18x)

231.21x = 788.64 + 118.296x

Collect like terms

231.21x — 118.296x = 788.64

112.914x = 788.64

Divide both side by 112.914

x = 788.64 /112.914

x = 7

Therefore the formula for the hydrated salt (MgSO4.xH2O) is MgSO4.7H2O

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