I would say that you would need 12 to have it be equal for this reaction to happen. I hope that this helped. :)
Answer:
The answer to the question is
The specific heat capacity of the alloy = 1.77 J/(g·°C)
Explanation:
To solve this, we list out the given variables thus
Mass of alloy = 45 g
Initial temperature of the alloy = 25 °C
Final temperature of the alloy = 37 °C
Heat absorbed by the alloy = 956 J
Thus we have
ΔH = m·c·(T₂ - T₁) where ΔH = heat absorbed by the alloy = 956 J, c = specific heat capacity of the alloy and T₁ = Initial temperature of the alloy = 25 °C , T₂ = Final temperature of the alloy = 37 °C and m = mass of the alloy = 45 g
∴ 956 J = 45 × C × (37 - 25) = 540 g·°C×c or
c = 956 J/(540 g·°C) = 1.77 J/(g·°C)
The specific heat capacity of the alloy is 1.77 J/(g·°C)
Explanation:
The relation between 
is given by :
Where :
= Ionic prodcut of water
The value of the first ionization constant of sodium sulfite = 
The value of 
:
The value of the second ionization constant of sodium sulfite = 
The value of 
:
Answer:
B
Explanation:
This is because the periodic table is designed this way.
