Prokaryotes divide by a form of asexual reproduction called binary fission in which Question 1 options: A cell divides into two
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<u>Answer:</u> Mass of nitrous oxide used is 264 grams and mass of oxygen gas used is 96 grams.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
....(1)
- <u>For a:</u> Combustion of ethylene in nitrous oxide
The chemical equation for the combustion of ethylene in nitrous oxide follows the equation:
By stoichiometry of the reaction;
6 moles of nitrous oxide are required for the complete combustion of ethylene molecule.
Calculating the mass of nitrous oxide using equation 1:
Molar mass of nitrous oxide = 44 g/mol
Moles of nitrous oxide = 6 moles
Putting values in equation 1, we get:
Thus, 264 grams of nitrous oxide are required for the complete combustion of ethylene.
- <u>For b:</u> Combustion of ethylene in air
The chemical equation for the combustion of ethylene in air follows the equation:
By stoichiometry of the reaction;
3 moles of oxygen are required for the complete combustion of ethylene molecule.
Calculating the mass of oxygen using equation 1:
Molar mass of oxygen = 32 g/mol
Moles of oxygen = 3 moles
Putting values in equation 1, we get:
Thus, 96 grams of oxygen are required for the complete combustion of ethylene.