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mart [117]
3 years ago
6

What will happen to the temperature if heat is added to an object the temperature is​

Chemistry
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

The temperature will rise as a matter of fact

Explanation:

Heat is the type of energy that travels from one point to another owing to temperature difference.

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A fruit and oatmeal bar contains 142 nutritional calories. Convert this energy to calories
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</span>A nutritional calorie<span>, or kilocalorie, is equal to 1000 calories.
</span>E = 142 kcal · 1000 cal/kcal.
E = 142 000 cal.
Calorie (cal)<span>, or small calorie, is the amount of energy needed to heat one gram of water by one degree Celsius.
</span><span>One small calorie is approximately 4.2 joules.
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8 0
3 years ago
B. Determine the percent composition of each element in NaCl. (1 point) Must show work to
andrey2020 [161]

Answer:

Sodium (Na): (.5 point)

22.99+35.453=58.433.   22.99/58.433=   39%

Chlorine (Cl): (.5 point)

22.99+35.453=58.433.   35.453/58.433= 61%

Explanation:

8 0
2 years ago
ASAP PLZ HELP CHEMISTRY!!! CALCULATE THE MEAN AND THE UNCERTAINTY FOR EACH EXPERIMENT!!!
STALIN [3.7K]

Answer:

MEANS:

1 = 97.7

2 = 74.3

3 = 50

4 = 30

5 = 13

UNCERTAINTY:

gimme a sec, ill put it in the comments under this

3 0
3 years ago
What particles in an atom are involved in nuclear reactions
VikaD [51]

Answer:

Explanation:

Electrons are the negatively charged particles of an atom that are involved in chemical reactions. They are located outside the nucleus of an atom

8 0
3 years ago
he rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate c
Leya [2.2K]

The question is incomplete, here is the complete question:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0 kJ/mol . If the rate constant of this reaction is 6.7 M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

<u>Answer:</u> The rate constant at 324°C is 61.29M^{-1}s^{-1}

<u>Explanation:</u>

To calculate rate constant at two different temperatures of the reaction, we use Arrhenius equation, which is:

\ln(\frac{K_{324^oC}}{K_{244^oC}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_{244^oC} = equilibrium constant at 244°C = 6.7M^{-1}s^{-1}

K_{324^oC} = equilibrium constant at 324°C = ?

E_a = Activation energy = 71.0 kJ/mol = 71000 J/mol   (Conversion factor:  1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 244^oC=[273+244]K=517K

T_2 = final temperature = 324^oC=[273+324]K=597K

Putting values in above equation, we get:

\ln(\frac{K_{324^oC}}{6.7})=\frac{71000J}{8.314J/mol.K}[\frac{1}{517}-\frac{1}{597}]\\\\K_{324^oC}=61.29M^{-1}s^{-1}

Hence, the rate constant at 324°C is 61.29M^{-1}s^{-1}

8 0
3 years ago
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