London dispersion
dipole-dipole
Yes, it does, just like any other sugar or substance
<span>Name of type of mechanism </span>initiation step<span> first </span>propagation step<span> second </span>propagation step<span>(ii) </span>write<span> an overall </span>equation<span> for the </span>formation of dichloromethane<span> from ... Best Answer: i) This is a </span>free-radical<span> substitution mechanism.</span>
