Answer: 15
The square root of 225 is 15.
Explanation:
https://api-project-1022638073839.appspot.com/questions/how-do-you-find-the-square-root-of-1849#642333
Answer:
the entropy change for the surroundings when 1.68 moles of Fe2O3(s) react at standard conditions = 49.73 J/K.
Explanation:
3Fe2O3(s) + H2(g)-----------2Fe3O4(s) + H2O(g)
∆S°rxn = n x sum of ∆S° products - n x sum of ∆S° reactants
∆S°rxn = [2x∆S°Fe3O4(s) + ∆S°H2O(g)] - [3x∆S°Fe2O3(s) + ∆S°H2(g)]
∆S°rxn = [(2x146.44)+(188.72)] - [(3x87.40)+(130.59)] J/K
∆S°rxn = (481.6 - 392.79) J/K =88.81J/K.
For 3 moles of Fe2O3 react, ∆S° =88.81 J/K,
then for 1.68 moles Fe2O3 react, ∆S° = (1.68 mol x 88.81 J/K)/(3 mol) = 49.73 J/K the entropy change for the surroundings when 1.68 moles of Fe2O3(s) react at standard conditions.
Answer:
Fe2O3 + C → 2Fe + CO3
Explanation:
The unbalanced equation given in this question is as follows:
Fe2O3 + C → Fe + C03
To balance this equation, one should ensure that the number of atoms of each element on both sides of the equation is equal. The balanced equation is as follows;
Fe2O3 + C → 2Fe + CO3
N.B, there are;
- 2atoms of Fe on both sides
- 1 atom of C on both sides
- 3 moles of O on both sides
K ---> 38.7 g / 39.1 g/mol = 0.99
N ---> 13.9 g / 14.0 g/mol = 0.99
O ---> 47.4 g / 16.0 g/mol = 2.96
Divide by smallest:
K ---> 0.99 / 0.99 = 1
N ---> 0.99 / 0.99 = 1
O ---> 2.96 / 0.99 = 3
KNO3
