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2 years ago

Millikan measured the quantity of charge carried

Chemistry

1 answer:

Cloud [144]2 years ago

6 0

Answer:

m = E × Q

And Q = I × t

m = E × I × t

Where m = mass in grams

Q = quantity of electricity in coulomb

I = current in ampere

t = time in seconds

E = electrochemical equivalent of the substance

Explanation:

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What is the formula of lead nitrate

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Explanation:

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Answer:

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<h2>properties of graphite:</h2>

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2 years ago

Hydrogen iodide, HI, is formed in an equilibrium reaction when gaseous hydrogen and iodine gas are heated together. If 20.0 g of

Kaylis [27]

Answer: D. 19.9 g hydrogen remains.

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

a) moles of $H_2$

$\text{Number of moles}=\frac{20.0g}{2g/mol}=10.0moles$

b) moles of $I_2$

$\text{Number of moles}=\frac{20.0g}{254g/mol}=0.0787moles$

$H_2(g)+I_2(g)\rightarrow 2HI(g)$

According to stoichiometry :

1 mole of $I_2$ require 1 mole of $H_2$

Thus 0.0787 moles of $l_2$ require= $\frac{1}{1}\times 0.0787=0.0787moles$ of $H_2$

Thus $l_2$ is the limiting reagent as it limits the formation of product and $H_2$ acts as the excess reagent. (10.0-0.0787)= 9.92 moles of $H_2$ are left unreacted.

Mass of $H_2=moles\times {\text {Molar mass}}=9.92moles\times 2.01g/mol=19.9g$

Thus 19.9 g of $H_2$ remains unreacted.

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2 years ago

El hipoclorito de sodio (NaClO), es vendido en una solución clara de ligero color verde-amarillento y un olor característico que

vivado [14]

Respuesta:

16,7 mL

Explicación:

Paso 1: Información provista

Concentración inicial (C₁): 6%

Volumen inicial (V₁): ?

Concentración final (C₂): 0,5%

Volumen final (V₂): 200 mL

Paso 2: Calcular el volumen de la solución concentrada

Queremos preparar una solución diluida de hipoclorito de sodio a partir de una concentrada. Podemos calcular el volumen inicial que debemos tomar usando la regla de dilución.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0,5% × 200 mL / 6% = 16,7 mL

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2 years ago