The melting points for the second series transition elements increase from 1526˚C for yttrium to 2623˚C for molybdenum and then
1 answer:
Answer:
The melting points of the second series of transition elements are electrons are entering to the type of orbital.
Explanation:
Transition elements have "d" band that can overlap with the "s' band to give a composite band. The composite band have six molecular orbitals per metal atom.
Half of the molecular orbitals are the anti bonding.So, maximum bonding occurs when the molecular orbitals contains six electrons i.e. the metal has six valence electrons per each metal atom.
When the maximum bonding occurs then it shows maximum melting point.
So, molybdenum shows melting point at and after that the electrons goes into the antibonding and reaches minimum for cadmium when the anti boning orbital is completely filled. So, the melting point of the cadmium is tex]321^{o}C[/tex].
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Answer:
Choose the least electronegative atom other than H.
Explanation:
A Lewis structure consists of <em>terminal atoms</em> and one or more <em>central atoms</em>.
H can be <em>only a terminal atom</em> because it can form only one bond.
So the central atom must be either C or O.
The central atom is the less electronegative atom: C.
So, start the Lewis structure with a central C atom.
Then attach an O atom to get C-O.
Finally, attach the H atoms.
The condensed formula often gives you a clue where they go.
The formula CH₃OH implies that there are 3 H atoms on C and one on O.
The connectivity of the atoms is then as in the diagram below.
