Determine the pH of a 0.461 M C6H5CO2H M solution if the Ka of C6H5CO2H is 6.5 x 10-5. Determine the pH of a 0.461 M C6H5CO2H M
solution if the Ka of C6H5CO2H is 6.5 x 10-5. 11.74 9.48 5.48 4.52 2.26
1 answer:
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Answer:
The specific heat of the metal is 0.466
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
The equation that allows calculating heat exchanges is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case:
- Q= 2330 J
- c= ?
- m= 25 g
- ΔT= 200 °C
Replacing:
2330 J= c*25 g* 200 °C
Solving:
c=0.466
<u><em>The specific heat of the metal is 0.466 </em></u><u><em></em></u>
<u>Answer:</u> The equilibrium concentration of HCl is
<u>Explanation:</u>
We are given:
Moles of = 0.564 moles
Volume of vessel = 1.00 L
Molarity is calculated by using the equation:
Molarity of
The given chemical equation follows:
<u>Initial:</u> 0.564
<u>At eqllm:</u> 0.564-x x x
The expression of for above equation follows:
The concentration of pure solid and pure liquid is taken as 1.
We are given:
Putting values in above equation, we get:
Negative sign is neglected because concentration cannot be negative.
So,
Hence, the equilibrium concentration of HCl is