In this question, you are given the density (2.7g/ml) and the volume of the aluminum. You are asked how much the volume is. To answer this question, you need to convert the volume into mass. Since the unit used is already same, you don't need to convert it into another unit. The calculation would be:
mass= volume / density
mass= 405ml / (2.70 g/ml)
mass= 150grams
A pure element unbound or in a diatomic state, such as cl2, always has an oxidation number of 0 (zero).
<h3>Why does pure element or a diatomic molecule has zero oxidation state?</h3>
In a neutral substance with atoms of only one element, the oxidation number of an atom is zero. As a result, the oxidation number of the atoms in O2, O3, P4, S8, and aluminum metal is 0. The oxidation numbers for an element in its normal state will be zero. O2 and Cl2 are diatomic gas molecules that occur naturally, thus when they are in that state, they have an oxidation state of zero. Metals like zinc will also have an oxidation number of zero if they are in their natural solid state.
O2 and Cl2 are neutral diatomic, hence they will always have a zero oxidation state. It is impossible for one oxygen atom to have a negative 2 charge while the other has a positive 2. The oxidation states should be 0 if the elements are solids, liquids, or any type of diatomic molecule.
Learn more about oxidation state here:
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Question: Given the balanced equation representing a reaction:
2H2 + O2 ==>2H2O
What is the total mass of water formed when 8 grams of hydrogen reacts completely with 64 grams of oxygen?
(1) 18 g (3) 56 g
(2) 36 g (4) 72 g
Answer:
"72 gram" is the total mass of water formed when 8 grams of hydrogen reacts completely with 64 grams of oxygen
Explanation:
We will do stoichiometry in this kind of problem:


Therefore, the total mass of water formed is 72 g.
Answer:
Final temperature is 302 K
Explanation:
You can now initial volume with ideal gas law, thus:
V = 
Where:
n are moles: 2 moles
R is gas constant: 0,082 
T is temperature: 300 K
P is pressure: 1 atm
V is volume, with these values: <em>49,2 L</em>
The work in the expansion of the gas, W, is: 1216 J - 34166 J = <em>-32950 J</em>
This work is:
W = P (Vf- Vi)
Where P is constant pressure, 1 atm
And Vf and Vi are final and initial volume in the expansion
-32950 J = -1 atm (Vf-49,2L) × 
Solving: <em>Vf = 49,52 L</em>
Thus, final temperature could be obtained from ideal gas law, again:
T = 
Where:
n are moles: 2 moles
R is gas constant: 0,082 
P is pressure: 1 atm
V is volume: 49,52 L
T is final temperature: <em>302 K</em>
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I hope it helps!
What it said chemistry and i was looking to answer something