What biological molecules transport other substances, provide structural
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Explanation:
The given precipitation reaction will be as follows.
Here, AgCl is the precipitate which is formed.
It is known that molarity is the number of moles present in a liter of solution.
Mathematically, Molarity =
It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.
Molarity =
0.269 M =
no. of moles = 0.306 mol
As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.
No. of moles =
0.307 mol =
mass = 43.99 g
Thus, we can conclude that mass of precipitate produced is 43.99 g.
The molarity of the solution will be 3.45 M
<h3>Further explanation </h3>Dilution is the process of adding a solvent to get a more dilute solution.
The moles(n) before and after dilution are the same.
Can be formulated :
M₁V₁=M₂V₂
M₁ = Molarity of the solution before dilution
V₁ = volume of the solution before dilution
M₂ = Molarity of the solution after dilution
V₂ = Molarity volume of the solution after dilution
The initial solution
345 mL of a 2.5 M NaCl solution.
M₁=2.5 M
V₁=345 ml
The solution after boiled :
V₂=250 ml