Answer:This reaction will be followed by TLC to monitor the progress of the oxidation. The camphor is then reduced by sodium borohydride to give the isomeric alcohol,
Explanation:
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Answer:
atoms of metallic element.
Dissolution and precipitation of _______ are the main processes that form limestone caves.
Answer: Calcite
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Answer:
23.55 L
Explanation:
USe the following 'identity' of gs laws
P1 V 1 / T1 = P2 V2 / T2 ( T must be in Kelvin)
re arrange to
P1 V 1 T2 / (T1 P2) = V2 NOW SUB IN THE VALUES
752 * 34.2 * ( 34 + 273.15) / [( 229 + 273.15) * 668] = V2 = 23.55 L
<u>Answer:</u> The molar concentration of ammonia is 3.008 M
<u>Explanation:</u>
To calculate the concentration of base, we use the equation given by neutralization reaction:
![n_1M_1V_1=n_2M_2V_2](https://tex.z-dn.net/?f=n_1M_1V_1%3Dn_2M_2V_2)
where,
are the n-factor, molarity and volume of acid which is ![HCl](https://tex.z-dn.net/?f=HCl)
are the n-factor, molarity and volume of base which is ![NH_3](https://tex.z-dn.net/?f=NH_3)
We are given:
![n_1=1\\M_1=0.800M\\V_1=18.8mL\\n_2=1\\M_2=?M\\V_2=5.00mL](https://tex.z-dn.net/?f=n_1%3D1%5C%5CM_1%3D0.800M%5C%5CV_1%3D18.8mL%5C%5Cn_2%3D1%5C%5CM_2%3D%3FM%5C%5CV_2%3D5.00mL)
Putting values in above equation, we get:
![1\times 0.800\times 18.8=1\times M_2\times 5.00\\\\x=\frac{1\times 0.800\times 18.8}{1\times 5.00}=3.008M](https://tex.z-dn.net/?f=1%5Ctimes%200.800%5Ctimes%2018.8%3D1%5Ctimes%20M_2%5Ctimes%205.00%5C%5C%5C%5Cx%3D%5Cfrac%7B1%5Ctimes%200.800%5Ctimes%2018.8%7D%7B1%5Ctimes%205.00%7D%3D3.008M)
Hence, the molar concentration of ammonia is 3.008 M