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svetoff [14.1K]
3 years ago
5

How many feet are there in a meter?

Physics
2 answers:
melisa1 [442]3 years ago
7 0
There is 3 feet and 3.37 inches
miv72 [106K]3 years ago
3 0
3.2808399 hope it helped
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What are three types of electromagnetic waves that are used to transmit information? What types of devices are used to receive e
MrMuchimi

Answer:

Three types of electromagnetic waves, used to transmit various information

Explanation:

A form of energy waves having both electric & magnetic fields are Electromagnetic waves. Three types -

Radio Waves - These have longest wavelengths & transmit data through radio, satellites, radar .

Micro Waves - These have shorter wavelengths & are used in cooking appliances & predicting weather.

X rays - These have more short wavelength and can penerate soft tissues like skin & muscle, hence are used for medical examining

3 0
3 years ago
Which of the following is a factor that determines the composition of magma?
Lina20 [59]
The answer is C. I hope I helped!
5 0
3 years ago
10m= (5.0) + (.5)(9.8)(5.0)
Norma-Jean [14]
M=2.45 because you multiply out the equation on the right and divide by 10
8 0
3 years ago
PLEASE HELP MEE PLEASE I BEG
TEA [102]

Explanation: (I think)

Plug your values into the momentum equation.

So m1= 63kg

m2 = 10 kg

V1 = 12 m/s

And then plug in your values and solve for your unknown (v2)

8 0
3 years ago
Holly puts a box into the trunk of her car. Later, she drives around an unbanked curve that has a radius of 48 m. The speed of t
LiRa [457]

Answer:

The minimum coefficient of friction is 0.544

Solution:

As per the question:

Radius of the curve, R = 48 m

Speed of the car, v = 16 m/s

To calculate the minimum coefficient of static friction:

The centrifugal force on the box is in the outward direction and is given by:

F_{c} = \frac{mv^{2}}{R}  

f_{s} = \mu_{s}mg

where

\mu_{s} = coefficient of static friction

The net force on the box is zero, since, the box is stationary and is given by:

F_{net} = f_{s} - F_{c}  

0 = f_{s} - F_{c}  

\mu_{s}mg = \frac{mv^{2}}{R}  

\mu_{s} = \frac{v^{2}}{gR}  

\mu_{s} = \frac{16^{2}}{9.8\times 48} = 0.544  

3 0
4 years ago
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