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svetoff [14.1K]
3 years ago
5

How many feet are there in a meter?

Physics
2 answers:
melisa1 [442]3 years ago
7 0
There is 3 feet and 3.37 inches
miv72 [106K]3 years ago
3 0
3.2808399 hope it helped
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A boat has a mass of 31,999 kg and a plane has a mass of 110,000 kg. What is the ratio of weight of the plane to the boat?
Gelneren [198K]

Answer:

3.44:1

Explanation:

We use ratios to find the ratio of weight.

 Mass of Plane= 110000 kg                          ∴ W= mg

 Mass of  Boat =31999 kg

\frac{weight of plane}{weight of boat}=\frac{110000*9.81}{31999*9.81}

 =\frac{3.44}{1}

SO 3.44:1

8 0
4 years ago
Read 2 more answers
When is the mass of an object if it exerts a force of 160 N and an acceleration of 8.15m/s^2
yan [13]

Answer:

f=ma.......m=f/a......m=20kg

4 0
3 years ago
How long does it take a car travelling at 80 m/s to decelerate to 18 m/s with an acceleration rate of -16m/s?
sertanlavr [38]
  • initial velocity=u=80m/s
  • Final velocity=v=18m/s
  • Acceleration=a=-16m/s^2
  • Time=t

We know

\boxed{\sf a=\dfrac{v-u}{t}}

\\ \sf\longmapsto t=\dfrac{v-u}{a}

\\ \sf\longmapsto t=\dfrac{18-80}{-16}

\\ \sf\longmapsto t=\dfrac{-62}{16}

\\ \sf\longmapsto t=3.8s

4 0
3 years ago
2. A person who weighs 800 N steps onto a scale that is
Fynjy0 [20]

Answer:

дешовок в гавне овц свиней xddddd

Explanation:

дешовок в гавне овц свиней xdddddдешовок в гавне овц свиней xdddddдешовок в гавне овц свиней xdddddдешовок в гавне овц свиней xdddddдешовок в гавне овц свиней xdddddдешовок в гавне овц свиней xddddd

6 0
2 years ago
At a certain instant, a rotating turbine wheel of radius RR has angular speed ωω (measured in rad/srad/s). What must be the magn
jonny [76]

Answer:

Explanation:

The magnitude of the acceleration makes an angle of 30° with the tangential velocity.

Resolving the acceleration to tangential and radial acceleration

at = aCos30 = √3a/2

ar = aSin30 = ½a

a = 2•ar

Then, the tangential acceleration is the linear acceleration, so the relationship between the tangential acceleration and angular acceleration is given as:

at = Rα

Then, α = at/R

since at = √3a/2

Then, α = √3 at/2R, equation 1

The radial acceleration is given as

ar = ω²R

Note that, at² + ar² = a²

at = √(a²-ar²)

Back to equation 1

α = √3 at/2R

α = √3√(a²-ar²)/2R

α = √3√(a²-(w²R)²)/2R

α = √3(a²-w⁴R²) / 2R

Also, a = 2•ar = 2w²R

Then,

α = √3((2w²R)²-w⁴R²) / 2R

α = √3(4w⁴R²-w⁴R²) / 2R

α = √3(3w⁴R²) / 2R

α = √9w⁴R² / 2R

α = 3w²R / 2R

α = 3w²/2

7 0
3 years ago
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