1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anit [1.1K]
3 years ago
15

Two long, straight wires, one above the other, are seperated by a distance 2a2a and are parallel to the x−axisx−axis. Let the +y

−axis+y−axis be in the plane of the wires in the direction from the lower wire to the upper wire. Each wire carries current II in the +x−direction+x−direction. Find B⃗ B→ - the net magnetic field of the two wires at the following points in the plane of the wires.
Physics
1 answer:
kompoz [17]3 years ago
3 0

Answer:

note:

<u>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment</u>

Download docx
You might be interested in
Suppose you want to determine the resistance of a resistor that is nominally 100 . You should be able to apply 10 V across the r
Butoxors [25]

Answer:

a) For y = 102 mA, R = 98.039 ohms

For y = 97 mA, R = 103.09 ohms

b) Check explanatios for b

Explanation:

Applied voltage, V = 10 V

For the first measurement, current y_{1} = 102 mA = 0.102 A

According to ohm's law, V = IR

R = V/I

Here, I = y_{1}

R = \frac{V}{y_{1} } \\R = \frac{10}{0.102} \\R = 98.039 ohms

For the second measurement, current y_{2} = 97 mA = 0.097 A

R = \frac{V}{y_{2} }

R = \frac{10}{0.097} \\R = 103 .09 ohms

b) y = \left[\begin{array}{ccc}y_{1} &y_{2} \end{array}\right] ^{T}

y = \left[\begin{array}{ccc}y_{1} \\y_{2} \end{array}\right]

y = \left[\begin{array}{ccc}102*10^{-3} \\97*10^{-3}  \end{array}\right]

A linear equation is of the form y = Gx

The nominal value of the resistance = 100 ohms

x = \left[\begin{array}{ccc}100\end{array}\right]

\left[\begin{array}{ccc}102*10^{-3} \\97*10^{-3}  \end{array}\right] =  \left[\begin{array}{ccc}G_{1} \\G_{2}  \end{array}\right] \left[\begin{array}{ccc}100\end{array}\right]\\\left[\begin{array}{ccc}G_{1} \\G_{2}  \end{array}\right] =  \left[\begin{array}{ccc}102*10^{-5} \\97*10^{-5}  \end{array}\right]

3 0
3 years ago
Please help I need this fast
Ghella [55]
The solution has reacted.
5 0
3 years ago
What are the methods that are used for heat transfer
Roman55 [17]

Answer:

Heat can travel from one place to another in three ways: Conduction, Convection and Radiation. Both conduction and convection require matter to transfer heat. If there is a temperature difference between two systems heat will always find a way to transfer from the higher to lower system.

Explanation:

Hope this helps

6 0
3 years ago
describe an experiment to show how the frequency of a note emitted by a vibrating string depends on the tension of the string
mart [117]
Easy ! 

Take any musical instrument with strings ... a violin, a guitar, etc.

The length of the vibrating part of the strings doesn't change ...
it's the distance from the 'bridge' to the 'nut'.

Pluck any string.  Then, slightly twist the tuning peg for that string,
and pluck the string again.

Twisting the peg only changed the string's tension; the length
couldn't change.

-- If you twisted the peg in the direction that made the string slightly
tighter, then your second pluck had a higher pitch than your first one.

-- If you twisted the peg in the direction that made the string slightly
looser, then your second pluck had a lower pitch than the first one.
3 0
3 years ago
A magnesium oxide component must not fail when a tensile stress of 10.5 MPa is applied. Determine the maximum allowable surface
Aloiza [94]

Answer:

Maximum permitted surface crack length is 1.29 mm

Explanation:

As per the question:

Tensile stress, \sigma = 10.5\ MPa = 10.5\times 10^{6}\ Pa

Surface energy of magnesium oxide, SE = 1.0\ J/m^{2}

Modulus of elasticity of the material, E = 225 GPa = 225\times 10^{9}\ Pa

Now,

To calculate the maximum allowable surface crack length:

L = \frac{2E\times SE}{\sigma^{2}\pi }

L = \frac{2\times 225\times 10^{9}\times 1.0}{10.5\times 10^{6}\times \pi } = 1.29\times 10^{- 3}\ m = 1.29\ mm

7 0
4 years ago
Other questions:
  • To what temperature must you raise a silver wire (c = 0.0038), originally at 20.0°C, to double its resistance, neglecting any ch
    9·1 answer
  • Which of the three recording stations was closest to the epicenter of the earthquake, based on the seismograms shown below?
    5·2 answers
  • The room contains a refrigerator, operated by an electric motor. The motor does work at the rate of 438 W when it is running. Th
    5·1 answer
  • 1. Which of the following is an accurate statement? A. Step-down voltage transformers have a different number of turns in the pr
    9·1 answer
  • Describe the difference between red light and blue light.
    5·1 answer
  • When you do glass blowing is it a chemical change or a physical change
    9·1 answer
  • Thinking about an analogue clock, calculate the angular displacement in revolutions, radians and degrees for the following: • A
    14·1 answer
  • A very rigid material—one that stretches or compresses only slightly under large forces—has a large value of __________.
    14·1 answer
  • A very long, straight wire has charge per unit length 3.20 x 10^-10 c&gt;m. At what distance from the wire is the electric-field
    7·1 answer
  • a hydraulic lift requires a minimum effort force force of 14.4N to lift a patient of mass 82kg .How much is the effort piston ar
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!