First find Acceleration
- Initial velocity=u=0m/s
- Final velocity=v=42m/s
- Time=t=2s
- Distance=s
- Acceleration=a
Using second equation of kinematics
Answer:
The velocity of the second car when it passes the first car is 40 m/s
Explanation:
The position and velocity of the cars is given by the following equations:
x = x0 + v0 · t + 1/2 · a · t²
v = v0 + a · t
Where:
x = position at time t
x0 = initial position
v0 = initial velocity
t = time
a = acceleration
v = velocity at time t
If the velocity is constant, then a = 0 and x = x0 + v · t
When the second car passes the first car, the position of both cars is the same:
x first car = x second car
x0 + v · t = x0 + v0 · t + 1/2 · a · t² (x0 = 0 and v0 = 0)
v · t = 1/2 · a · t²
2 · v /a = t
2 · 20 m/s / 2.0 m/s² = t
t = 20 s
Using the equation of velocity, we can calculate the velocity of the second car at t = 20 s
v = v0 + a · t
v = 0 m/s + 2.0 m/s² · 20 s = 40 m/s
The velocity of the second car when it passes the first car is 40 m/s
Answer:
the answer is most likely likely to be 2
Answer:
D. ) The force would be zero newtons
Explanation:
Because
If you are at the center of the earth, gravity is zero because all the mass around you is pulling "up" (every direction there is up!)
So F=mg so if g is zero F is also zero
Answer:
aerodynamics
Explanation:
if an object like a car is going 200 mph at max speed and then the car gets aerodynamic or smoothed to the point that air can get by the car it could end up going another 20 mph faster